Simplify by combining the like terms.
x + 5 - 2x + 3 = 8 - x
7 - 3x - 1 = 6 - 3x
8 - x = 6 - 3x
8 = 6 - 2x
2 = -2x
x = -1
Check by plugging -1 into the original equation.
-1 + 5 - (-2) + 3 = 7 - (-3) - 1
9 = 9
It checks.
by 4. You do this because you want to find out what x equals. If you divide by 16, you find out what 1/4X equals, and that isn't much good to you. x=4 is the answer.
You find, or construct, an equation or set of equations which express the unknown variable in terms of other variables. Then you solve the equation(s), using algebra.You find, or construct, an equation or set of equations which express the unknown variable in terms of other variables. Then you solve the equation(s), using algebra.You find, or construct, an equation or set of equations which express the unknown variable in terms of other variables. Then you solve the equation(s), using algebra.You find, or construct, an equation or set of equations which express the unknown variable in terms of other variables. Then you solve the equation(s), using algebra.
substitution
As usual when solving equations, you need to "isolate" the variable, in this case, the variable "x". 4x means 4 times x; if you divide both sides of the equation (the left side and the right side) by 4, you will have achieved this.
An equation with a variable is a math problem with a missing number that you have to find out using some specific steps that you are taught. Example: 4+n=5. If you want to find out what the variable is, you have to do the OPPOSITE OPPERATION and find it out. So I would take the answer, and do the opposite operation and then the answer is the variable. Of course there are MUCH harder variable equations. :D
Substitute the variable in the denominator for a value that will make the denominator have a value of 0 or an imaginary number
by 4. You do this because you want to find out what x equals. If you divide by 16, you find out what 1/4X equals, and that isn't much good to you. x=4 is the answer.
It depends on the form of the equation.
Substitution
substitution
substitution
I have the feeling that you were looking to find a value for each variable in this equation. Unfortunately you can only solve for each variable in terms of the other variables in this equation.
Find values for the variable that satisfy the equation, that is if you replace those values for the variable into the original equation, the equation becomes a true statement.
You find, or construct, an equation or set of equations which express the unknown variable in terms of other variables. Then you solve the equation(s), using algebra.You find, or construct, an equation or set of equations which express the unknown variable in terms of other variables. Then you solve the equation(s), using algebra.You find, or construct, an equation or set of equations which express the unknown variable in terms of other variables. Then you solve the equation(s), using algebra.You find, or construct, an equation or set of equations which express the unknown variable in terms of other variables. Then you solve the equation(s), using algebra.
The goal is to find what value or values the variable may have, to make the equation true.
The variable term, X^3, is a third order polynomial term and will render three solutions, though one of those may be zero.
substitution