-3x2+12x-1 = y
Solve the quadratic equation when y = 0 by means of the quadratic equation formula which gives x values of 3.914854216 and 0.085145784.
Add these values together and divide them by 2 which is 4/2 = 2 and this is the line symmetry of the parabola.
Substitute 2 for x into the original equation to find the value of y:
So the vertex is at (2, 11)
Remember that the parabola has a maximum value because the coefficient of x2 is negative in other words it will face downwards.
1
No. For example, a 12x1 and a 4x3 quadrilateral both have an area of 12, but they are not congruent.
12x1=12 12x2=24 12x3=36 12x4=48 12x5=60 12x6=72
364 1x12=12 2x11=22 3x10=30 4x9=36 5x8=40 6x7=42 7x6=42 8x5=40 9x4=36 10x3=30 11x2=22 12x1=12 Added up equals 364
Ok.The midpoint formula: [(x1 + x2)/2, (y1 + y2)/2]So for instance if your coordinates were endpoint : (-8,10) and the Midpoint: (-2,6)By substituting the given values into the formula we have:(x1 + -8)/2 = -2 and (y1 + 10)/2 = 6x1 - 8 = -4 and y1 + 10 = 12x1 -8 + 8 = -4 + 8 and y1 + 10 - 10 = 12 - 10x1 = 4 and y1 = 2so the endpoints coordinates are ( 4, 2)
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24x1 12x1
12x1 6x2 4x3 Thats it
12x1
34.12
60
since 12 is a multiple of 3 and itself (12x1), 12 is the LCM of 3 and 12
No. For example, a 12x1 and a 4x3 quadrilateral both have an area of 12, but they are not congruent.
3N = 3x14 = 4212H = 12x1 = 121As = 754O = 4x16 = 64Total = 193 g/mole
5x114.3. Center Bore: 67.1. Hardware: 12x1. 50 Lug Offset: 45-55mm
12x1=12 12x2=24 12x3=36 12x4=48 12x5=60 12x6=72
364 1x12=12 2x11=22 3x10=30 4x9=36 5x8=40 6x7=42 7x6=42 8x5=40 9x4=36 10x3=30 11x2=22 12x1=12 Added up equals 364