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-3x2+12x-1 = y

Solve the quadratic equation when y = 0 by means of the quadratic equation formula which gives x values of 3.914854216 and 0.085145784.

Add these values together and divide them by 2 which is 4/2 = 2 and this is the line symmetry of the parabola.

Substitute 2 for x into the original equation to find the value of y:

So the vertex is at (2, 11)

Remember that the parabola has a maximum value because the coefficient of x2 is negative in other words it will face downwards.

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Q: How do you find the vertex of the parabola given by y equals -3x2 plus 12x-1?
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