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∙ 13y ago-3x2+12x-1 = y
Solve the quadratic equation when y = 0 by means of the quadratic equation formula which gives x values of 3.914854216 and 0.085145784.
Add these values together and divide them by 2 which is 4/2 = 2 and this is the line symmetry of the parabola.
Substitute 2 for x into the original equation to find the value of y:
So the vertex is at (2, 11)
Remember that the parabola has a maximum value because the coefficient of x2 is negative in other words it will face downwards.
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∙ 13y ago1
No. For example, a 12x1 and a 4x3 quadrilateral both have an area of 12, but they are not congruent.
364 1x12=12 2x11=22 3x10=30 4x9=36 5x8=40 6x7=42 7x6=42 8x5=40 9x4=36 10x3=30 11x2=22 12x1=12 Added up equals 364
12x1=12 12x2=24 12x3=36 12x4=48 12x5=60 12x6=72
Ok.The midpoint formula: [(x1 + x2)/2, (y1 + y2)/2]So for instance if your coordinates were endpoint : (-8,10) and the Midpoint: (-2,6)By substituting the given values into the formula we have:(x1 + -8)/2 = -2 and (y1 + 10)/2 = 6x1 - 8 = -4 and y1 + 10 = 12x1 -8 + 8 = -4 + 8 and y1 + 10 - 10 = 12 - 10x1 = 4 and y1 = 2so the endpoints coordinates are ( 4, 2)
1
24x1 12x1
12x1 6x2 4x3 Thats it
12x1
34.12
60
since 12 is a multiple of 3 and itself (12x1), 12 is the LCM of 3 and 12
No. For example, a 12x1 and a 4x3 quadrilateral both have an area of 12, but they are not congruent.
364 1x12=12 2x11=22 3x10=30 4x9=36 5x8=40 6x7=42 7x6=42 8x5=40 9x4=36 10x3=30 11x2=22 12x1=12 Added up equals 364
The molar mass of (NH4)3AsO4 is calculated by summing the molar masses of each element present. This includes nitrogen (N), hydrogen (H), arsenic (As), and oxygen (O). By adding up the molar masses of each element in the compound, the molar mass of (NH4)3AsO4 is found to be approximately 202.02 g/mol.
5x114.3. Center Bore: 67.1. Hardware: 12x1. 50 Lug Offset: 45-55mm
12x1=12 12x2=24 12x3=36 12x4=48 12x5=60 12x6=72