At any point on the y-axis, the x-coordinate is zero.
In the equation of the parabola, set x=0. Tidy it up, and you have " Y = the y-intercept ".
The intercept of a graph is the point where is crosses one of the coordinate axes. The x intercept is where it crosses the x axis, the y intercept where it crosses the y axis. If the graph is given as y equals a function of x, it is usually easier to find the y intercept, because that is where x is 0. You just plug in 0 for x and evaluate. To find the x intercept, you plug in 0 for y and then you have to solve an equation for x. This is fairly easy if it is a linear equation (the graph is a straight line), somewhat harder for a quadratic (a parabola). But anyway you only asked for a definition, and I have given it.
The y intercept will be the ordinate(y value) in the given co-ordinate.
When the slope is undefined, you know the line has to be vertical. Vertical lines only have an x in their equations. When you have the coordinates (2,4) with a vertical line, the equation for the slope intercept AND standard form would be the same thing: x=2
5
Factorise equation, and look at what x values are needed for the equation to equal zero. Eg. x^2+5x+6 (x+3)(x+2)=0 So parabola intercepts x axis at -3 and -2.
If you know the equation, you just plug in x = 0 and solve.
-8
-2, 6
The intercept of a graph is the point where is crosses one of the coordinate axes. The x intercept is where it crosses the x axis, the y intercept where it crosses the y axis. If the graph is given as y equals a function of x, it is usually easier to find the y intercept, because that is where x is 0. You just plug in 0 for x and evaluate. To find the x intercept, you plug in 0 for y and then you have to solve an equation for x. This is fairly easy if it is a linear equation (the graph is a straight line), somewhat harder for a quadratic (a parabola). But anyway you only asked for a definition, and I have given it.
12
The y-intercept is c in the standard form. The x-intercept is -c/m.
Consider a parabola described by the expression y = ax2 + bx + c first, calculate it's first and second derivatives: y' = 2ax + b y'' = 2a Find x value at which y' = 0, and calculate whether the corresponding y-coordinate is above or below the x-axis. If it's above the x-axis, then the parabola will not intercept the x-axis if y'' is greater than 0. If it's below the x-axis, then the parabola will not intercept the x-axis if y'' is less than 0. Otherwise, it will always intercept the x axis at two locations.
y = {slope}x + {y intercept}
The y intercept will be the ordinate(y value) in the given co-ordinate.
Remember the standard form of an equation:Y = (slope) x + (y-intercept)Now take your equationY = (-1) x + (0)Compare yours to the standard one.That's how to find them.Now can you identify the slope and y-intercept of the graph of your equation ?
When the slope is undefined, you know the line has to be vertical. Vertical lines only have an x in their equations. When you have the coordinates (2,4) with a vertical line, the equation for the slope intercept AND standard form would be the same thing: x=2
5