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The method you use will depend on what the questions are, and

there will be some questions for which it won't be possible.

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11y ago

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Related Questions

What is the enrichment of 16 only using 1 2 3 and 4?

only using the numbers once


What times what that equals 43?

If you are not concerned with the numbers being round, then there are an infinite number of answers to this. If, on the other hand, you want to stick to round numbers, then there are very few answers: 1 * 43 -1 * -43 43i * -i -43i * i If you only want real integers, then you're down to two answers: 1 * 43 -1 * -43 And if you only want natural numbers, then there's only one answer: 1 * 43 This is because 43 is a prime number, and has no factors.


How do you get the number 13 using only numbers 1 and 5 and 7 and 8 using the numbers only once?

8 plus 1 , minus 5, plus 7 + 13


What and what equal -13?

There are an infinitely many possible answers. Using only whole numbers you have . . . , -2 and -11, -1 and -12, 0 and -13, 1 and -14, 2 and -15, . . . You can then consider numbers to 1 decimal place and then 2 decimal places and 3, and so on etc.


What are the even numbers upto 100 using only the numbers 1 3 5 and 7?

== == == == == == == == == ==


What number goes into 170 and 12?

The only answers are 1 and 2. Meaning 1 and 2 are the only numbers that you can divide 170 and 12 by and get whole numbers (no decimals) as answers. 170 / 1 = 170 12 / 1 = 12 170 / 2 = 85 12 / 2 = 6 Try it with any other number and you'll see that at least one of your answers will not be a whole number.


What is a method for representing numbers using only 0 and 1?

binary system


What are the answers to the four fours questions from 1-100 using only fours?

101


How many 3 digit numbers can you make using the numbers 1 5 and 9 only using them once in every number?

3! = 6.


Can the answers of factorials be decimals?

No. Factorials can only be placed on positive whole numbers or 0. For example, 0!, 1!, and 6! are all fine, but 2.5! and (-1)! are not. Since factorials can only be placed on whole numbers, that means you will only be multiplying whole numbers. 100! = 100 * 99 * 98 ... * 1; all those numbers are whole numbers, meaning your answer will be a whole number.


How do you get the number 23 using only the numbers 5 1 12?

12+5+5+1


Is 1 divided by 4 possible?

0.25