998,000
3! = 6.
17 = (4+2)*3 - 1
it cant
only using the numbers once
998,000
3! = 6.
17 = (4+2)*3 - 1
it cant
6*5*4*3=360
only using the numbers once
61
567 - 349 = 218 or 567 - 218 = 349
-9
18
2,5,13,647,809
QUESTION* can you only use each number once, or can you use them multiple times?