0: (5x5)-(5x5)
1: (5:5)+5-5
2: (5:5)+(5:5)
3: (5+5+5):5
4: [(5x5)-5]:5
5: [(5-5)x5]+5
6: [(5x5)+5]:5
7: [(5+5):5]+5
10: 5+5+5-5
11: (5:5)+5+5
15: (5x5)-5-5
20: 5+5+5+5
24: (5x5)-(5:5)
25: (5x5)+5-5
26: (5x5)+(5:5)
30: [(5:5)+5]x5
35: (5x5)+5+5
45: [(5+5)x5]-5
50: (5x5)+(5x5)
55: [(5+5)x5]+5
75: (5+5+5)x5
120: (5x5x5)-5
130: (5x5x5)+5
625: 5x5x5x5
101
how do i make 17 using only 2 4 6 8
1
No. Not if the numbers are to be used only once. There is only one 5 (or a multiple of 5) in the numbers available. Using times and divide cannot produce any more of them. On the other hand 100 is divisible by 5*5 so at least two fives are required. If the numbers can be used more than once then 2*2*5*5 is one possible solution.
Have a pair of dice where one has only sixes and one only fives, for example.Have a pair of dice where one has only sixes and one only fives, for example.Have a pair of dice where one has only sixes and one only fives, for example.Have a pair of dice where one has only sixes and one only fives, for example.
Michigan touches all of the Great Lakes except for Ontario.
You can't unless something is missing in your question.
4*6+1
There are an infinite number of numbers with only four factors, started by 6, 8 and 10.
All of them, but it does depend on what operators are allowed.
Only four numbers:20233032
5 divided by 5, plus 5