No. Not if the numbers are to be used only once.
There is only one 5 (or a multiple of 5) in the numbers available. Using times and divide cannot produce any more of them. On the other hand 100 is divisible by 5*5 so at least two fives are required.
If the numbers can be used more than once then 2*2*5*5 is one possible solution.
You can make 75 using the numbers 7, 6, 5, and 3 by using the following equation: ( (7 \times 6 \times 5) - 3 = 75 ). Here, you multiply 7, 6, and 5 to get 210 and then subtract 3 to arrive at 75.
Add all of the numbers up, and then divide that result by how many numbers there were, e.g. 1,2,3,4,5. Added up they make 15. As there are five numbers there, you divide 15 by 5, and you get 3. Voila.
1234
You divide it by 186.166666666667 and you get 24! :)
Using 1, 2, and 3, you can make 27 whole numbers.
You divide them by nine
add them all together and then divide the answer by the number of numbers.
You divide 7 by 4 which is 1.75.
12 + 24 * 6/18 = 12 + 24 *1/3 = 12 + 8 = 20
7+9+10-6-8
8 of them.
You can make 75 using the numbers 7, 6, 5, and 3 by using the following equation: ( (7 \times 6 \times 5) - 3 = 75 ). Here, you multiply 7, 6, and 5 to get 210 and then subtract 3 to arrive at 75.
1290
Add all of the numbers up, and then divide that result by how many numbers there were, e.g. 1,2,3,4,5. Added up they make 15. As there are five numbers there, you divide 15 by 5, and you get 3. Voila.
If the only operation is addition, then 3.
1234
You divide it by 186.166666666667 and you get 24! :)