Q: How many four digits numbers using 1 2 3 4 once only are divisible by 4?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

numbers that are divisible by 4 is either: 4n or numbers in which the number formed by last two digits are divisible by 4

If the last two digits are divisible by four, the whole number is divisible by four. If the number can be cut in half twice, it's divisible by four.

1047, 1407, 4017, 4071 are four (out of eight) such numbers.

321 is divisible by these four numbers: 1, 3, 107, 321.

3*3*2*1 = 18 of them.

Related questions

numbers that are divisible by 4 is either: 4n or numbers in which the number formed by last two digits are divisible by 4

Yes.

All multiples of four are divisible by four.

288 is divisible by 2 because it's even. 288 is divisible by 3 because the sum of its digits is a multiple of 3. 288 is divisible by 4 because the last two numbers are divisible by 4. 288 is divisible by 9 because the sum of its digits is a multiple of 9.

If the last two digits of a number are divisible by four, the whole number is divisible by four.

Whole numbers are divisible by 4 if the number formed by the last two individual digits is evenly divisible by 4. For example, the number formed by the last two digits of the number 2628 is 28, which is evenly divisible by 4 so the number 2628 is evenly divisible by 4.

If the digits are all different then 18. Otherwise, 192.

If the last two digits are divisible by four, the whole number is divisible by four. If the number can be cut in half twice, it's divisible by four.

Yes. For future reference, if the last two digits of any number are divisible by 4, then the number itself will always be divisible by 4.

1234

2222

1047, 1407, 4017, 4071 are four (out of eight) such numbers.