(5 - 4) x 3 = 3.
5*(3-4/2) = 5*(3-2) = 5*1 = 5
5 * 5 + 3 - 4 is one way.
To rewrite (3(4 + 5)) using the distributive property, you distribute the 3 to both terms inside the parentheses. This means you multiply 3 by 4 and 3 by 5: [ 3(4 + 5) = 3 \cdot 4 + 3 \cdot 5 = 12 + 15. ] So, (3(4 + 5) = 12 + 15).
(5/5-1)+3+1+4.
The simplest, probably, is 2 + 3 + 4 - 5
How about: (5+3) to the power 4 = 4096
First way: (3/3 + 5) * 4 = 24 Second way: (5-3) * (4*3) = 24
5+4-3+2
4 x 5 + 6 - 3!
x^(-5/3) = 4 1/x^(5/3) = 4 x^(5/3) = 1/4 [x^(5/3)]^(3/5) = (1/4)^(3/5) x = 1/4^(3/5) or, x = 4^(-3/5) Check: x^(-5/3) = 4 [4^(-3/5)]^(-5/3) = 4 ? 4 ^(15/15) = 4 ? 4^1 = 4 ? 4 = 4
5+3=8 8-4=4 4*6=24
5! / 4 - 2 * 3