(5/5-1)+3+1+4.
(2(4 + 1) - 3)
4^2+3+1
(4! - 3)*1*2
106------------------------------------------------------------------------------------------------From Rafaelrz.You can make, 4P3 = 4!/(4-3)! = 24, different 3 digit numbers using 1, 2, 3 and 4.
2 * 4! - 1 - 3 = 44
It could be done by: (3*3)/(3*3) = 1
(4 + 3 + 1) x 2 = 16
1/3+2/3=14/4=13/1*1/3=1
32 - 4 + 1 =29
To make 24 using 1, 3, 4, and 6, you can use the following mathematical operations: (6 / (1 - (3/4))). This equation breaks down as follows: first, divide 6 by (1 - (3/4)), which simplifies to 6 / (1 - 0.75) = 6 / 0.25 = 24. Therefore, using these numbers and operations, you can make 24.
3*(2*4 + 1) = 3*(8 + 1) = 3*9 = 27
(4 x 3 - 1) x 2 = 22