Write down the number and 1. Divide by two. Write down 14 and 2. Divide by two. Write down 7 and 4. Stop.
(28,1)(14,2)(7,4)
The factor pairs of 28 are :28,114,27,4
The factor pairs of 28 are 1*28, 2*14, and 4*7
There are 3 factor pairs of 28. 28 = 1 x 28 28 = 2 x 14 28 = 4 x 7
28 has three factor pairs which are:28 = 1 x 2828 = 2 x 1428 = 4 x 7
28,114,27,4
1,282,144,7-1,-28-2,-14-4,-7
1 & 28, 2 & 14, 4 & 7
1, 28 2, 14 4, 7
1 and 28 2 and 14 4 and 7
The factor pairs of 112 are 1*112, 2*56, 4*28, 7*16, and 8*14
The factor pairs of 56 are: 1, 56; 2, 28; 4, 14; 7, 8 Therefore, if you exclude itself and 1, there are three factor pairs, but if you include itself and 1, there are four factor pairs.
The factor pairs of 56 are 1 x 56, 2 x 28, 4 x 14, and 7 x 8.