There are a lot of useful techniques. If it's a sequence defined recursively, like
an = an-1 / 2
then you can set an = an-1 and solve for that. If it's defined more simply, like
an = 1/2n, you can consider the behaviour of the sequence as n goes to infinity (These are both the same sequence, with limit 0).
I don't think either of these ways are really considered rigorous though, even though they lead you to the correct answer. To formally prove the convergence of a sequence, you can either use the delta-epsilon or the Cauchy method if it is in Rk
In the delta-epsilon method, you just need to show that for any ε > 0, there exists a δ such that if you have two n1, n2 so that |n1 - n2| < δ, d(an1 - an2) < ε.
To show a function fulfills the Cauchy criterion, you need to show that for any ε > 0, you can find an N so that for all n1, n2 > N, d(an1 - an2) < ε, but this is only a valid proof of convergence in Rk
A finite sequence has a beginning and an end, whereas an infinite sequence has no end.
A convergent sequence is an infinite sequence whose terms move ever closer to a finite limit. For any specified allowable margin of error (the absolute difference between each term and the finite limit) a term can be found, after which all succeeding terms in the sequence remain within that margin of error.
An infinite sequence.
It is a sequence which goes on and on - for ever.
If a monotone sequence An is convergent, then a limit exists for it. On the other hand, if the sequence is divergent, then a limit does not exist.
It is an arithmetic sequence for which the index goes on and on (and on).
The existence of matter is not infinite, as there is a limit to the amount of matter in the universe.
The answer is undefined becaus infinite has no limit.
An example of an infinite geometric sequence is 3, 5, 7, 9, ..., the three dots represent that the number goes on forever.
finite, has a limit
No, such a sequence is not posible.
yup