It is sqrt(3) times length of an edge. How to figure. The diagonal across one face is sqrt(2) * edge [make a right triangle: the hypotenuse will be that diagonal].
Now make another right triangle, with the diagonal across the face as one 'leg', and an edge as the other 'leg'. The hypotenuse of this triangle will be a diagonal of the cube: Length of this = sqrt((leg1)2 + (leg2)2) = sqrt((edge)2 + (sqrt(2)*edge)2) = sqrt(edge2 + 2*(edge)2) = sqrt(3*(edge)2) = sqrt(3)*(edge)
A cube has four space diagonals. One from each of the four vertices on the top face of the cube to the opposite vertex on the other face
The side of a square is is cube root of 2cm. Find the length of the diagonals.
60
The 2 diagonals bi-sect each other at right angles which is 90 degrees
20 Perhaps the author of the previous answer could explain his working. It seems to me that there are two diagonals on each face (total 12), plus 4 internal diagonals, giving an answer of 16.
I would assume the answer is 12, as a square has 2 diagonal lines, and a cube is really just six squares.
1. Cube has all sides equal whereas cuboid doesn't. 2. Cube has all diagonals equal whereas cuboid doesn't.
1243 KDA= Iota Cube
find the cube root of 125(which is 5) is the length of one side do Pythagorean theorem to find the diagonal 5squared plus 5 squared=50 square root of 50=7.07106781 is diagonal
1/2*(n2-3n) = number of diagonals Rearranging the formula: n2-3n-(2*diagonals) = 0 Solve as a quadratic equation and taking the positive value of n as the number of sides.
It is: 2
A undecagon has 44 diagonals. A dodecagon has 54 diagonals. An octagon has 20 diagonals. A heptagon has 14 diagonals.