1/2*(n2-3n) = number of diagonals
Rearranging the formula: n2-3n-(2*diagonals) = 0
Solve as a quadratic equation and taking the positive value of n as the number of sides.
In a polygon with ( n ) sides, the number of diagonals that can be drawn from one vertex is given by the formula ( n - 3 ). For a polygon with 35 sides, this means you can draw ( 35 - 3 = 32 ) diagonals from one vertex. Thus, from one vertex in a 35-sided polygon, you can draw 32 diagonals.
The polygon with 5 diagonals is a heptagon. A heptagon has seven sides, and the formula for calculating the number of diagonals in a polygon is given by ( \frac{n(n-3)}{2} ), where ( n ) is the number of sides. For a heptagon, substituting ( n = 7 ) yields ( \frac{7(7-3)}{2} = 5 ) diagonals.
The formula is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
Using the formula: 0.5*(142-42) = 77 diagonals
It has 10 sides because using the formula 0.5*(102-30) = 35 diagonals
In a polygon with ( n ) sides, the number of diagonals that can be drawn from one vertex is given by the formula ( n - 3 ). For a polygon with 35 sides, this means you can draw ( 35 - 3 = 32 ) diagonals from one vertex. Thus, from one vertex in a 35-sided polygon, you can draw 32 diagonals.
Using the formula (x)(x-3)/2 = Diagonals ; simply replace the diagonals with the number of diagonals you're given. Then, you'll havev (x)(x-3)/2 = Diagonals. Simplify it, and you'll be given x(power of 2) - 3X = (2)(Diagonals). Subtract the amount of diagonals from both sides, and you'll have x(power of 2) - 3X - 2Diagonals = 0. From there, use the quadratic formula to find the number of sides the polygon has.
There is no such polygon that fits the given information.
The polygon with 5 diagonals is a heptagon. A heptagon has seven sides, and the formula for calculating the number of diagonals in a polygon is given by ( \frac{n(n-3)}{2} ), where ( n ) is the number of sides. For a heptagon, substituting ( n = 7 ) yields ( \frac{7(7-3)}{2} = 5 ) diagonals.
It is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
The formula is: 0.5*(n2-3n) = diagonals whereas n is the number of sides of the polygon
It is: 0.5*(n2-3n) = diagonals whereas 'n' is the number of sides of the polygon
Using the formula: 0.5*(142-42) = 77 diagonals
It has 10 sides because using the formula 0.5*(102-30) = 35 diagonals
The formula is: 0.5*(n2-3n) where n is the number of sides of the polygon
0.5*(n2-3n) where n is equal to the number of sides of the polygon
You can find the number of diagonals in a polygon using the formula n(n-3)/2, where n is the number of sides. Therefore an 11 sided polygon has 44 diagonals.