7 people and 14 hands?
21 times
14 is incorrect Correct answer is 21* 7 persons in total, which means the first one will shake hands with 6 persons, the next in line will shake hands with 5 (given that he already shook hands with the first person). Calculation is: 6+5+4+3+2+1=21 *Applies to question if handshakes take place between new partners only, however in either case 14 can never be the answer.
There will be 45 handshakes (assuming that each person doesn't repeat who they shake hands with). Use the following formula for this one (n*(n-1))/2 where n is number of people...so if 10 people its (10 x 9) / 2 = 45 handshakes, if 7 people its (7 x 6) / 2 = 21 handshakes etc.
The Man Who Would Not Shake Hands - 2013 was released on: USA: 7 July 2013
One Day at a Time - 1975 Shake Hands 7-3 was released on: USA: 25 October 1981
For everyone to shake hands with everyone else, there are 21 handshakes. (below copied from my answer of a similar question) This is an arithmetic progression and can be solved with the equation Sn=(1+(n-1))(n-1)/2 where Sn is the total sum of handshakes for n people. NB: I have used n-1 instead of n in the equation for the sum of an arithmetic progression, because you're not really going to shake hands with yourself, so you don't include the nth term, in this case 7. Alternatively, you can solve this geometrically by drawing a heptagon, drawing lines between all the vertices, and then adding all the lines up.
The total number of handshakes that occur when each of seven persons shakes hands with each of the other six persons can be calculated using the combination formula. The formula for calculating the number of combinations of n items taken r at a time is nCr = n! / (r!(n-r)!). In this case, n = 7 and r = 2 (since each handshake involves 2 people), so the total number of handshakes is 7C2 = 7! / (2!(7-2)!) = 7! / (2!5!) = (7*6) / 2 = 21. Therefore, a total of 21 handshakes would occur in this scenario, not 42.
The first guy shakes hands with 6 other people. The next guy has already shaken the first one's hand, so she has only 5 other people to handshake & so on down to the last two people with a single handshake. All together there are 6 + 5 + 4 + 3 + 2 + 1 = 21 handshakes
45: 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1
20 hand shakes would take place. Here's how: 1234567 23456 34567 4567 567 67 7 And a person can't shake his own hand or someones hands twice
55 10+9+8+7+6+5+4+3+2+1=55
9+8+7+6+5+4+3+2+1=45