One way is (5 - 3)*sqrt(4)*6
Assuming all of {7, 8, 2, 3} have to be used exactly once: (8 - 2) x (7 - 3) = 24.
(5+7)*(5-3)=12*2=24
24 of them.
24
To get 24 using 1 3 4 and 6 once you do 6 times 4
24
(7+6-5) x 3 = 8 x 3 = 24
It could be that if: 3+6+7+x = 24 The: x = 8
By using: (3*6)+(3*2) = 24
9-5=4 7-4=3 3*8=24
4*3*2*1 = 24
4! * 2 - 1 - 3 =24*2 - 1 - 3 = 48 - 1 - 3 = 44