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To form a three-digit number using the digits 0-9, the first digit cannot be 0 (as it would not be a three-digit number). Thus, the first digit can be any of the digits from 1 to 9 (9 options). The second and third digits can each be any digit from 0 to 9 (10 options each). Therefore, the total number of three-digit numbers is (9 \times 10 \times 10 = 900).
That depends a lot on how often you may repeat each digit, and what operations are allowed. If you just want to write a four-digit number, using each digit once, start by writing the largest digit on the left, then continue with the second-largest, etc.
3201
what is the greets possible 9 digit number that uses each of the digits 1-3 times
There are 5 digits in the number 67392. Each digit represents a place value in the number, with the leftmost digit being the ten-thousands place and the rightmost digit being the ones place. In this case, the digits are 6, 7, 3, 9, and 2.
Assign the digits from left to right, using the largest possible digit in each case. Don't forget to reserve an even digit for the last position.
22412
To form a three-digit number using the digits 0-9, the first digit cannot be 0 (as it would not be a three-digit number). Thus, the first digit can be any of the digits from 1 to 9 (9 options). The second and third digits can each be any digit from 0 to 9 (10 options each). Therefore, the total number of three-digit numbers is (9 \times 10 \times 10 = 900).
That depends a lot on how often you may repeat each digit, and what operations are allowed. If you just want to write a four-digit number, using each digit once, start by writing the largest digit on the left, then continue with the second-largest, etc.
3201
what is the greets possible 9 digit number that uses each of the digits 1-3 times
There are 5 digits in the number 67392. Each digit represents a place value in the number, with the leftmost digit being the ten-thousands place and the rightmost digit being the ones place. In this case, the digits are 6, 7, 3, 9, and 2.
Assuming that 2356 is a different number to 2365, then: 1st digit can be one of four digits (2356) For each of these 4 first digits, there are 3 of those digits, plus the zero, meaning 4 possible digits for the 2nd digit For each of those first two digits, there is a choice of 3 digits for the 3rd digit For each of those first 3 digits, there is a choice of 2 digits for the 4tj digit. Thus there are 4 x 4 x 3 x 2 = 96 different possible 4 digit numbers that do not stat with 0 FM the digits 02356.
Assuming each digit only once: 65432 (and no further mathematical operations).
Six: 234, 243, 324, 342, 423, and 432.
By the sum of its digits: 10. By each of its individual digits: 11.
A delectable number has nine digits, using the numbers 1-9 once in each digit. The first digit of a delectable number must be divisible by one. The first and second digits must be divisible by two, the first through third must be divisible by three, etc. There has only been one delectable number discovered: 381654729.