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What is the equation 2y plus 10 equals Xdefines?
2y + 10 = x can be written as y = x/2 - 5. This defines a straight line graph with a slope of 1/2 and a y intercept of -5.
What is the y-intercept of the graph of 2y-5x equals 14?
To find the y-intercept of 2y - 5x = 14, we can set x = 0 and solve for y.2y - 5(0) = 142y = 14y = 7So the y-intercept occurs at (0, 7).
What is the slope and y-intercept of the graph of -x plus 2y equals 6?
-x+2y = 6 2y = x+6 y = 1/2x+3 Therefore the slope is 1/2 and the y intercept is 3
What is the locus of points that satisfies both equations 2x-3y equals 5 and x-2y equals 1?
2x-3y=5 and x-2y=12x-3y+2y=5 and x-2y+2y=12x-y=5 and x=12(1)-y=52-y=52-y-2=5-2-y=3y=-3(x,y) is (1,-3)
2Y equals X plus 4 in a graph?
2y = x + 4Divide each side by 2:y = (1/2)x + 2The graph is a straight line with a slope of (1/2) and a y-intercept of 2.
Which point is on the graph of 5x-2y equals 4?
When y=4, x=8/5
What is the equation 2y plus 10 equals Xdefines?
2y + 10 = x can be written as y = x/2 - 5. This defines a straight line graph with a slope of 1/2 and a y intercept of -5.
How would you graph the problem x plus 2y or equal to 5?
to graph something you must put it in slope-intercept form y=mx+b so it would be 2y=-x+5 but you must get the y alone so the final answer must be y=-1/2x+2.5. 2.5 is the y intercept and 5 is the slope
Graph the line 5x-10 equals 2y?
2y = 5x - 10Putting into Slope-Intercept form, we have y = 5/2 x - 5. So, the y-intercept is -5 and the slope is 5/2 or 2.5. (x-intercept is 2).
How do you graph the equation x plus 2y equals 4?
First, write out the problem: x+2y=4 then you have to simplify it so that only y is on one side x+2y=4 -4 -4 x+2y-4=0 -2y -2y x-4=-2y / -2 = -1/2x + 2 = y then, draw out a graph: and, let's say, x=4, then you plug that into the equation, and solve for y in this case, if x=4, then y=0, so one of the points would be (4, 0)
What is the y-intercept of the graph of 2y-5x equals 14?
To find the y-intercept of 2y - 5x = 14, we can set x = 0 and solve for y.2y - 5(0) = 142y = 14y = 7So the y-intercept occurs at (0, 7).
What is the slope and y-intercept of the graph of -x plus 2y equals 6?
-x+2y = 6 2y = x+6 y = 1/2x+3 Therefore the slope is 1/2 and the y intercept is 3
What is the locus of points that satisfies both equations 2x-3y equals 5 and x-2y equals 1?
2x-3y=5 and x-2y=12x-3y+2y=5 and x-2y+2y=12x-y=5 and x=12(1)-y=52-y=52-y-2=5-2-y=3y=-3(x,y) is (1,-3)
2Y equals X plus 4 in a graph?
2y = x + 4Divide each side by 2:y = (1/2)x + 2The graph is a straight line with a slope of (1/2) and a y-intercept of 2.
What is the y-intercept for the graph of the equation 3x - 2y equals 5?
Put in function form. 3X - 2Y = 5 - 2Y = - 3X + 5 Y = 3/2X - 5/2 Y intercept = - 5/2
How do you Substitute x equals y plus 3 into x plus 2y equals 9?
x = y+3 x+2y = 9 => x = 9-2y y+3 = 9-2y 2y+y = 9-3 3y = 6 y = 2 and x = 5
Can you tell me how to graph -2x equals 2y plus 5?
-2x=2y+5 +2x -2y -2y=2x+5 /-2 y=-1/1+2.5
