x2 + 10x + y2 + 20y - 19 = 0
x2 + 10x + y2 + 20y = 19
Complete the squares on the LHS:
x2 + 10x + 25 + y2 + 20y + 100 = 19 + 25 + 100 = 144
Simplify LHS:
(x + 5)2 + (y + 10)2 = 122
This is the equation of all points whose distance form the point (-5, -10) is 12 units. That is, the circle with centre (-5, -10) and radius = 12 units.
It is a straight line equation that needs to be rearranged into slope-intercept form as follows:- 8x+20y = -80 20y = -8x-80 y = -0.4x-4
12y - 4 = 7y + 165y = 20y = 4
Multiply first equation by 3 and second equation by 5:30x + 27y = 12, -30x + 20y = -25; add these two:47y = -13, making y = -13/47 and x = -61/94I have checked these values against the original equations and they satisfy both. Weird solution tho'!
12x - 9y = 6, 12x + 20y = 64 29y = 58 y = 2 x = 2
8x + 20y
15x-20y= 7 5y-3 +10x
0
4x + 20y
It is a straight line equation that needs to be rearranged into slope-intercept form as follows:- 8x+20y = -80 20y = -8x-80 y = -0.4x-4
x isn't in the calculation so it cant be solved.
12y - 4 = 7y + 165y = 20y = 4
If: 9y-20y = 25 Then: y = -25/11
5x + 4y = 204y = -5x + 20y = (-5/4)x + 5
Multiply first equation by 3 and second equation by 5:30x + 27y = 12, -30x + 20y = -25; add these two:47y = -13, making y = -13/47 and x = -61/94I have checked these values against the original equations and they satisfy both. Weird solution tho'!
12x - 9y = 6, 12x + 20y = 64 29y = 58 y = 2 x = 2
8x + 20y
ça ne marche pas...