If: 10X = 2.7 then X = 2.7/10 => 0.27
x=-8
Ok so your equation reads like this (I assume you forgot the +): 3 - 4x = 10x +10 The goal is to get the x's on one side and the other numbers on the other. It doesnt matter which side has which, so I will move the numbers to the right and the x's to the left. So first subtract 3 from both sides: 3 - 3 - 4x = 10x + 10 - 3 -4x = 10x + 7 Now subtract 10x from both sides. -4x - 10x = 10x - 10x + 7 -14x = 7 Now that we have like terms on both sides, all you need to do is divide both sides by -14 to solve for x. -14x / -14 = 7 / -14 x = -1 / 2
-10x = -50 Divide both sides by -10 remembering that a minus divided by a minus the quotient then becomes positive: x = 5 So: -10*5 = -50
12x + 9 = 10x + 1 Subtract 10x from both sides: 2x + 9 = 1 Sutract 9 from both sides: 2x = - 8 Divide both sides by 2: x = -4
10x-2x =8x-527
10x=x 9x=0 x=0
If: 10X = 2.7 then X = 2.7/10 => 0.27
11x = 10x-19 Subtact 10x fromboth sides:- x = -19
10x
10x+7=(-3) 10x=(-10) x=(-1)ans
10x - 3 = 17 Add 3 to both sides: 10x = 20 Divide both sides by 10: x = 2
12x - 6 = 10x +2 12x - 10x = 2 + 6 2x = 8 x = 4
well you divide by ten that's it the answer is 0.33333
0.9
Given: x2 + 10x - 16 Let: x2 + 10x - 16 = 0 x2 + 10x - 16 = 0 ∴ x2 + 10x + 25 = 16 + 25 ∴ (x + 5)2 = 41 ∴ x = -5 ± √41 ∴ x2 + 10x - 16 = (x + 5 + √41)(x + 5 - √41)
x=-8