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What is one fourth of two?
2 x 1/4 = 1/2
How can i graph c -4 2 and slope 3 2?
You can graph X -4 2 and slope 3 2 by first finding the values of X and Y and then using those values to sketch your graph.
How do you graph fx-x-1 3 gx-x-2 and hx -3x-1?
graph G(x)=[x]-1
How many times does the graph of y equals x2-4x plus 4 intersect the x-axis?
y=x2-4x+4 y = (x-2)(x-2) x=2 the graph only crosses the x-axis at positive 2. this is the minimum of the graph and the only point that is crosses the x-axis.
How many times does 2 and one fourth go into 50?
2(1/4)x=50 x=50/(2(1/4) x=28.57 your answer is 28.57
How can the graph of a fourth degree polynomial have its only x intercepts 0 1 and 2?
Easy. Same thing as the graph of f(x) = x^2 + 1 which have NO intercept.
What is one half of one fourth of one fourth of a gallon?
1/32 of a gallon (4 X 4 X 2).
What is one fourth of two?
2 x 1/4 = 1/2
What is the answer of one-fourth times 2?
1/4 x 2 is 1/2
How can you translate the graph of y equals x to obtain the graph of y equals x-4 plus 2?
y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.
Graph of fourth degree equation?
Every polynomial defines a function. A function of fourth degrees have a form such as,f(x) = ax^4 + bx^3 + cx^2 + dx + e = 0, where a is different than 0For example, let's graph f(x) = x^4 - 2x^2 +1 (Here the terms with x^3, and x, are missed. I gave this example because students need to know that a fourth degree equation exists even though is different from the general formula. Since it has the power of 4, it still is a fourth degrees equation)Solution:Step 1. Use the Leading Coefficient Test to determine the graph's end behavior.Because the degrees of f(x) = 1x^4 - 2x^2 + 1 is even (n = 4) and the leading coefficient , 1, is positive, the graph rises to the left and rises to the right.Step 2. Find x-intercepts by setting f(x) = 0 and solve the resulting polynomial equation.x^4 - 2x^2 + 1 = 0 factor; use the formula (a - b)^2 = (a - b)(a- b)((x^2 -1)(x^2 -1) = 0 factor completely; use the formula (a^2 - b^2) = ( a - b)(a + b);(x - 1)(x +1)(x - 1)(x + 1) = 0(x - 1)(x - 1)(x +1)(x +1) = 0(x - 1)^2(x + 1)^2 = 0 solve for x;x = 1 or x = -1 you have double roots here; so,the graph touches x-axis at -1 and 1 and turns around.Step 3. Find the y-intercept by computing f(0).f(x) = x^4 - 2x^2 + 1f(0) = 0^4 - 2(0)^2 + 1 = 1There is a y-intercept ay i, so the graph passes through (0, 1).Step 4. use possible symmetry to help draw the graph. It will be y-axis symmetry. Let,s verify this by finding f(-x).f(x) = x^4 - 2x^2 + 1f(-x) = (-x)^4 - 2(-x)^2 +1f(-x) = x^4 - 2x^2 + 1Because f(-x) = f(x), the graph of f is symmetric with respect to the y-axis.You are able to graph now.Step 5. Use the fact that maximum number of turning points of the graph is n -1 to check whether it is drawing correctly. because you are graphing f(x) = x^4 - 2x^2 + 1, with n = 4, the maximum number of turning points is 4 -1 or 3. So, your graph will have 3 turning points, if it has more, you have violated the maximum number possible.Verify this observation.
What is one half of one fourth of one fourth of one fourth of a gallon?
0.25 x 0.25 x 0.25 x 0.5 = 0.0078125 gals
Which of the quadratics has a graph with only one x-intercept?
Quadratics that can be written in the form y = a*(x - r)2
Where does the graph of x2 - x - 2 y cross the x-axis?
y = x^2 - x - 2 This is the graph of a parabola. We need to find the x-intercepts. Set 0 for y, and solve for x: 0 = x^2 - x - 2 0 = (x + 1)(x - 2) x + 1 = 0 or x - 2 = 0 x = -1 or x = 2 Thus, x-intercepts are -1 and 2. The graph of y = x^2 - x - 2 crosses the x-axis at x = -1 and x = 2.
Graph x equals y plus 2?
x=y+2 y=x-2 The y value at the x axis (x=0) will be -2, so graph (0, -2). Let's calculate a few more points by varying x and calculating y: if x=2, y=2-2=0 (2, 0) similarly: (1, -1) (5, 3) Graph those points, then draw a line connecting them all. That's the graph of x=y+2.
How can i graph c -4 2 and slope 3 2?
You can graph X -4 2 and slope 3 2 by first finding the values of X and Y and then using those values to sketch your graph.
How do you graph fx-x-1 3 gx-x-2 and hx -3x-1?
graph G(x)=[x]-1
