0
y = x^2 - x - 2
This is the graph of a parabola. We need to find the x-intercepts. Set 0 for y, and solve for x:
0 = x^2 - x - 2
0 = (x + 1)(x - 2)
x + 1 = 0 or x - 2 = 0
x = -1 or x = 2
Thus, x-intercepts are -1 and 2. The graph of y = x^2 - x - 2 crosses the x-axis at x = -1 and x = 2.
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What does the graph look like for this equation y x2 10x 25?
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1.5
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What does the graph look like for this equation y x2 10x 25?
if y = x2 + 10x + 25 then y = (x + 5)2 This tells us that the graph would be a parabola, with it's vertex at (-5, 0), and a range of 0 to infinity.
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X squared minus x minus 2 graph?
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