y = x^2 - x - 2
This is the graph of a parabola. We need to find the x-intercepts. Set 0 for y, and solve for x:
0 = x^2 - x - 2
0 = (x + 1)(x - 2)
x + 1 = 0 or x - 2 = 0
x = -1 or x = 2
Thus, x-intercepts are -1 and 2. The graph of y = x^2 - x - 2 crosses the x-axis at x = -1 and x = 2.
if y = x2 + 10x + 25 then y = (x + 5)2 This tells us that the graph would be a parabola, with it's vertex at (-5, 0), and a range of 0 to infinity.
x2 - x - 2 = 0(x - 2)(x + 1) = 0x = 2 and -1
1.5
Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.
y = x^(2) y^(2) = 4ax Parabola on its side_ x^(2) + y^(2) + 2fx + 2gx +c = 0 ( A Circle) x^(2)/a + y(2) / b = 1 ( An Ellipse) x^(3) = A Cubic Graph with an 'S' curve.
x2+(y-x2/3)2=1
the graph is moved down 6 units
you need 2 points on the line y2-y1 slope=----- x2-x1
Say you have y=x2 -4x +4 y=(x-2)(x-2) x*x=x2 x*-2=-2x -2*x=2x -2*-2=4 x2 -4x +4
y=x2-4x+4 y = (x-2)(x-2) x=2 the graph only crosses the x-axis at positive 2. this is the minimum of the graph and the only point that is crosses the x-axis.
Given two coordinates (x1,y1) and (x2,y2) The midpoint is ( ((x2+x1)/2) , ((y2+y1)/2) )
Y=X^2 is a function for it forms a parabola on a graph.
The graph of that equation is a circle, centered at the origin, with radius = 2 .
Distance between the two points (x1 , y1) and (x2 , y2) is square root of [ (y2 - y1)2 + (x2 - x1)2 ]
if y = x2 + 10x + 25 then y = (x + 5)2 This tells us that the graph would be a parabola, with it's vertex at (-5, 0), and a range of 0 to infinity.
x2 + y - 49 = 0y = -x2 + 49First, plot the graph of y = -x2, with a vertex (0, 0), then translate it 49 units up. The vertex becomes (0, 49), which is a maximum point (the parabola opens downward).Or make a table to obtain several corresponding y-values for x = -3, -2, -1, 0, 1, 2, 3. Plot the points (x, y), and draw the graph of y = -x + 49.
x2 - x - 2 = 0(x - 2)(x + 1) = 0x = 2 and -1