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1 + 23 + 4 + 5 + 67 = 100 is one way.

1 + 2 + 34 + 56 + 7 = 100 is another.

1 + 2 + 3 + 4 + 5 + 6 + 7 = 28 so you need to move two non-adjacent digits that sum to 8 into the tens' places.

This is because:

Start with a sum of 28

Lose two digits that sum to 8 from the units so that you have 28 - 8 = 20

Gain two digits that in the tens place that sum to 8 so that 20 + 80 = 100.

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10y ago

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