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43-2x1

24 x3-1

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Q: How do you make 41 using 1 2 3 and 4?
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Related questions

How do you make 46 using 1 2 3 4 only once?

41 + 2 + 3 = 46


What are the factors of 41 and 82?

1, 41 1, 2, 41, 82


What are the factors for 82?

The factors of 82 are 1, 2, 41, and 82.


What is the answers 41-2-2?

Explanation: 41-2-2=37 ( 41-2=39)(39-2=37) 41 40 39 38 37 A simple way is: (41-40=39/39-38=37) This is because you take one every time. To make it simple you count backwards or to make it even simpler think it as counting from 1 to 2 but in reverse so that would make 2 to1. Because you take one/or count backwards each time but instead of taking 1 for your answer you just take 2 instead. DID YOU GET THAT


How do you make 29 using 1 2 3 and 4 using bodmas?

(2(4 + 1) - 3)


How do you solve x squared -4x equals 41?

x² - 4x = 41 → x² -4x - 41 = 0 Using the quadratic formula: x = (-b ± √(b² - 4ac))/(2a) → x = (4 ± √(4² - 4×1×-41)/(2×1) → x = (4 ± √(4(4+41)))/2 → x = (4 ± 2√45)/2 → x = 2 ± √45 → x = 2 + √45 (≈ 8.708) or x = 2 - √45 (≈ -4.708)


How many times does 2 go into 83?

41 with remainder 1.


How do you make 3 using the digits 1 2 and 3?

3 * (2 - 1)


How do you make 16 using 3 2 1?

(3 + 1)2 = 16


What are the factors and prime factors of 82?

82 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 4 factors of 82 are 1, 2, 41, and 82.The factor pairs of 82 are 1 x 82 and 2 x 41.The proper factors of 82 are 1, 2, and 41 or,if the definition you are using excludes 1, they are 2 and 41.The prime factors of 82 are 2 and 41.The 2 distinct prime factors (listing each prime factor only once) of 82 are 2 and 41.The prime factorization of 82 is 2 x 41.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple because "common" refers to factors or multiples that two or more numbers have in common.


What is 41 divided by 2?

20.5


What is 41 divided by 2 in the form of a fraction?

20.5