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What is the square of 41 using the square of a term of two terms?
412 = (40 + 1)2 = 402 + 2*40*1 + 12 = 1600 + 80 + 1 = 1681
Can you make 41 cents out of ten coins?
Yes. 5*1 cent 3*2 cents 1*10 cents 1*20 cents make 41 cents (in the Eurozone). The question did not exclude Euro and [Euro]cents.
What are the continuous division method of 82?
82/2 = 41/41 = 1 2 x 41 = 82
What 2 whole numbers can be multiplied to get 41?
1 and 41.
How can you make all the number 1-100 using just 1 2 3 and 4?
you can make them all using 1, 1-1=0 1=1 1+1=2 1+1+1=3 etc.
How do you make 46 using 1 2 3 4 only once?
41 + 2 + 3 = 46
What are the factors of 41 and 82?
1, 41 1, 2, 41, 82
What are the factors for 82?
The factors of 82 are 1, 2, 41, and 82.
What is the answers 41-2-2?
Explanation: 41-2-2=37 ( 41-2=39)(39-2=37) 41 40 39 38 37 A simple way is: (41-40=39/39-38=37) This is because you take one every time. To make it simple you count backwards or to make it even simpler think it as counting from 1 to 2 but in reverse so that would make 2 to1. Because you take one/or count backwards each time but instead of taking 1 for your answer you just take 2 instead. DID YOU GET THAT
What is the square of 41 using the square of a term of two terms?
412 = (40 + 1)2 = 402 + 2*40*1 + 12 = 1600 + 80 + 1 = 1681
How do you solve x squared -4x equals 41?
x² - 4x = 41 → x² -4x - 41 = 0 Using the quadratic formula: x = (-b ± √(b² - 4ac))/(2a) → x = (4 ± √(4² - 4×1×-41)/(2×1) → x = (4 ± √(4(4+41)))/2 → x = (4 ± 2√45)/2 → x = 2 ± √45 → x = 2 + √45 (≈ 8.708) or x = 2 - √45 (≈ -4.708)
Can you make 41 cents out of ten coins?
Yes. 5*1 cent 3*2 cents 1*10 cents 1*20 cents make 41 cents (in the Eurozone). The question did not exclude Euro and [Euro]cents.
What are the continuous division method of 82?
82/2 = 41/41 = 1 2 x 41 = 82
How do you make 29 using 1 2 3 and 4 using bodmas?
(2(4 + 1) - 3)
What 2 whole numbers can be multiplied to get 41?
1 and 41.
What are the factors and prime factors of 82?
82 is a composite number because it has factors other than 1 and itself. It is not a prime number.The 4 factors of 82 are 1, 2, 41, and 82.The factor pairs of 82 are 1 x 82 and 2 x 41.The proper factors of 82 are 1, 2, and 41 or,if the definition you are using excludes 1, they are 2 and 41.The prime factors of 82 are 2 and 41.The 2 distinct prime factors (listing each prime factor only once) of 82 are 2 and 41.The prime factorization of 82 is 2 x 41.NOTE: There cannot be common factors, a greatest common factor, or a least common multiple because "common" refers to factors or multiples that two or more numbers have in common.
What is 41 divided by 2?
20.5
