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Q: How do you make numbers using five fives?

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(55-5)/(5+5)

55----------------------------------------------------------------------------------------------From Rafaelrz.You can make, 5! = 120, five digit numbers using 1,2,3,4 and 6.

(5/5)5 = 1

55/5 = 11 - (5+5) = 1

(5 cubed - 5 - 5 + 5) / 5= 24

You add up all the numbers except one of the fives and then take that total and subtract it by the five you didn't use

101

It's done by: 5+5/5-5/5 = 5

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120

You have five numbers that add up to 115. What is the average value of those five numbers? Now, how do you choose five consecutive numbers that have that average value?

it is 1 7 tens 1 fives

1234

10+5+5/2 ten plus five plus five divided by 2

12.

The only solution that I know of is a bit of a cheat:5*(5 + 5) - 5/(.5 recurring).

5-1/5= 4 4/5 *5 = 24

Using 1, 2, and 3, you can make 27 whole numbers.

No. Not if the numbers are to be used only once. There is only one 5 (or a multiple of 5) in the numbers available. Using times and divide cannot produce any more of them. On the other hand 100 is divisible by 5*5 so at least two fives are required. If the numbers can be used more than once then 2*2*5*5 is one possible solution.

2,3,5and7

Twenty quarters will make five dollars. Fifty dimes will make five dollars. Five hundred pennies will make five dollars. Twenty dimes and twelve quarters will make five dollars. Of course, there are millions of combinations that you could use with US coins, excluding nickels, to make five dollars.

With whole numbers, there are five ways.

5x.6.Five 5's to get 35 - 5/5 - 5/5 = 5 - 1 - 1 = 3

One possible solution: (3 + 3)*(1*3/3 + 3) = 6 * 4 = 24

12, 13, 14, 15, 16