(5/5)5 = 1
One possible solution: (3 + 3)*(1*3/3 + 3) = 6 * 4 = 24
5x.6.Five 5's to get 35 - 5/5 - 5/5 = 5 - 1 - 1 = 3
3 fives of 40 = 15 of 40 = 6003 fives of 40 = 15 of 40 = 6003 fives of 40 = 15 of 40 = 6003 fives of 40 = 15 of 40 = 600
3 and 7/10
3. They are 755, 575 and 557.
To make five fives equal five, you can use the mathematical operation of factorial. By expressing five as 5! (5 factorial), which is equal to 5 x 4 x 3 x 2 x 1, and then subtracting 5 - 4 - 3 - 2 - 1, you will get the result of 5. Therefore, mathematically, 5! - 4 - 3 - 2 - 1 = 5.
You add up all the numbers except one of the fives and then take that total and subtract it by the five you didn't use
The probability of getting three fives in the first three rolls and non-fives in the next three rolls is; P(5,5,5,N5,N5,N5) = 1/6 x 1/6 x 1/6 x 5/6 x 5/6 x 5/6 = 0.002679... The number of different order in which the fives can come out is given by; 6C3 = 6!/[3!∙(6-3)!] = 20 So the probability that in 6 rolls of a fair die exactly three fives (in any order) will come out is; P(three fives any order) = (20)∙(1/6)3∙(5/6)3 = 0.05358... ~ 5.4%
3 * (2 - 1)
(2(4 + 1) - 3)
The product is 15
(1+1+1)! = 3! = 3x2x1 = 6... :)