multiply it by itself and then multiply that by the original number. example: 2 cubed. 2*2=4 4*2=8
Using a calculator will make it easier
by one by one
9*4*2 = 72
0
Multiply the digit to the left of the "decimal" point by 2^0 = 1. Multiply the digit to the left of it by 2^1 = 2 Multiply the digit to the left of that by 2^2 = 4 and so on. Also Multiply the digit to the right of the "decimal" point by 2^(-1) = 1/2. Multiply the digit to the right of that by 2^(-2) = 1/4 and so on. Add all these together. Example: Binary 1101.1011 1*2^3 = 1*8 = 8 1*2^2 = 1*4 = 4 0*2^1 = 0*2 =0 1*2^0 = 1*1 = 1 1*2^-1 = 1*1/2 = 0.5 0*2^-2 = 0*1/4 = 0 1*2^-3 = 1*1/8 = 0.125 1*2^-4 = 1*1/16 = 0.0625 Sum = 13.6875
21978
If this is a homework assignment, please consider trying it yourself first, otherwise the value of the reinforcement to the lesson offered by the homework will be lost on you.There are 60 possibilities that can be made for a three digit number using the numbers 2 4 6 8 and 9. (5 choices for the first digit, 4 choices for the second digit, and 3 choices for the third digit - multiply 5, 4, and 3, and you get 60.)To determine how many of these three digit numbers are smaller than 500, consider that, given 2 4 6 8 and 9, the first digit would have to be 2 or 4. That gives 2 choices for the first digit, 4 choices for the second digit, and 3 choices for the third digit. Multiply 2, 4, and 3, and you get 24.
If you multiply 2*9, you get 18. Multiply that by 10 to get a three digit number, and you get 180.
There are two answers to this question; When you multiply 1738 by 4 you get 6952 When you multiply 1963 by 4 you get 7852
Example: 222*12 222 3 digit * 13 2 digit ------- 666 Multiply 3 to all three twos +222 Multiply 1 to all three twos (skip spot) -------- 2886 Answer Add up
4 over 10 (multiply by 2), 8 over 20 (multiply by 4), 12 over 30 (multiply by 6) Simply multiply the numerator (the top digit in the problem) and the denominator (the bottom digit inthe problem) by the same number. This finds multiples of both numbers that are in the same proportion to each other as the original problem.