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To multiply a number by a one-digit number, start by writing the larger number above the smaller one, aligning the digits to the right. Multiply each digit of the larger number by the one-digit number, starting from the rightmost digit, carrying over any values as necessary. Write each result below the line, and if there are any carries, add them to the next left digit's product. Finally, sum all the results to get the final product.
The smallest two-digit odd number is 11. It is the first odd number that falls within the range of two-digit numbers, which start from 10.
Here is the best way to do two digit times two digit multiplication. Start by multiplying the bottom right number by the top right number. Then put down the digit in the ones place and carry the number in the tens place (if you have one). Then multiply the bottom right number by the top left number. To that number, add the number of tens you carried(3x3=9+2=11). put that answer down next the first number, making it(if the first number you put down is 1, 111. Now onto the second digit.put a zero underneath one digit in the answer you got(111) Multiply the bottom left number by the top right number. Put the digit in the ones place (7, for example) down, next to the zero, and carry the number you had in the tens place. Multiply the bottom left number by the top left number. Place both of those numbers (if u have more than one) by the seven which is next to the zero. Add the numbers you have on the bottom. EXAMPLE: 111 + 370 ----------------------------- 481 ( this is your answer) Please note that the problem wasn't real... And was just an example for the steps of two digit multiplication.
In the number 6.1237, the digit 3 is in the thousandths place. This means that the place value of the digit 3 is 0.003. The digit 3 represents three thousandths in this number.
2!, 3!, 4!, etc. carry:=0; % Start a multiply by n. for i:=1 to last do % Step along every digit. d:=digit[i]*n + carry; % The classic multiply. digit[i]:=d mod Base; % The low-order digit of the result. carry:=d div Base; % The carry to the next digit. next i; while carry > 0 % Store the carry in the big number. if last >= Limit then croak("Overflow!"); % If possible! last:=last + 1; % One more digit
You put the four digit number at the top of the three digit number and you do the same thing as you would do with a two digit number with a 3 digit number.
To find the product of 23 and 18, you would use the standard multiplication method. Start by multiplying the units digit of the first number (3) by the units digit of the second number (8), which equals 24. Write down the 4 and carry over the 2. Then, multiply the units digit of the first number by the tens digit of the second number, and vice versa, and add the carried over digit. Finally, multiply the tens digit of the first number by the tens digit of the second number and add it to the total. The result of 23 x 18 is 414.
Oh, dude, let me break it down for you. So, if you multiply a 4-digit number by a 2-digit number, the product can actually be either a 5-digit number or a 6-digit number, depending on the numbers you choose. It's like a surprise every time you hit that multiplication button! So, no, it's not always a 6-digit number, it's like a math lottery, man.
1We can not start a three digit number with 0, so 1 is the smallest digit.
Start Select the three digit number two hundred forty two. End.
No. Three-digit numbers start with 100.
The smallest two-digit odd number is 11. It is the first odd number that falls within the range of two-digit numbers, which start from 10.
Here is the best way to do two digit times two digit multiplication. Start by multiplying the bottom right number by the top right number. Then put down the digit in the ones place and carry the number in the tens place (if you have one). Then multiply the bottom right number by the top left number. To that number, add the number of tens you carried(3x3=9+2=11). put that answer down next the first number, making it(if the first number you put down is 1, 111. Now onto the second digit.put a zero underneath one digit in the answer you got(111) Multiply the bottom left number by the top right number. Put the digit in the ones place (7, for example) down, next to the zero, and carry the number you had in the tens place. Multiply the bottom left number by the top left number. Place both of those numbers (if u have more than one) by the seven which is next to the zero. Add the numbers you have on the bottom. EXAMPLE: 111 + 370 ----------------------------- 481 ( this is your answer) Please note that the problem wasn't real... And was just an example for the steps of two digit multiplication.
In the number 6.1237, the digit 3 is in the thousandths place. This means that the place value of the digit 3 is 0.003. The digit 3 represents three thousandths in this number.
There is no such number. You can start with a different number and end with different ones.
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2!, 3!, 4!, etc. carry:=0; % Start a multiply by n. for i:=1 to last do % Step along every digit. d:=digit[i]*n + carry; % The classic multiply. digit[i]:=d mod Base; % The low-order digit of the result. carry:=d div Base; % The carry to the next digit. next i; while carry > 0 % Store the carry in the big number. if last >= Limit then croak("Overflow!"); % If possible! last:=last + 1; % One more digit