Here is the best way to do two digit times two digit multiplication. Start by multiplying the bottom right number by the top right number. Then put down the digit in the ones place and carry the number in the tens place (if you have one). Then multiply the bottom right number by the top left number. To that number, add the number of tens you carried(3x3=9+2=11). put that answer down next the first number, making it(if the first number you put down is 1, 111. Now onto the second digit.put a zero underneath one digit in the answer you got(111) Multiply the bottom left number by the top right number. Put the digit in the ones place (7, for example) down, next to the zero, and carry the number you had in the tens place. Multiply the bottom left number by the top left number. Place both of those numbers (if u have more than one) by the seven which is next to the zero. Add the numbers you have on the bottom. EXAMPLE: 111 + 370 ----------------------------- 481 ( this is your answer) Please note that the problem wasn't real... And was just an example for the steps of two digit multiplication.
2!, 3!, 4!, etc. carry:=0; % Start a multiply by n. for i:=1 to last do % Step along every digit. d:=digit[i]*n + carry; % The classic multiply. digit[i]:=d mod Base; % The low-order digit of the result. carry:=d div Base; % The carry to the next digit. next i; while carry > 0 % Store the carry in the big number. if last >= Limit then croak("Overflow!"); % If possible! last:=last + 1; % One more digit
If multiplying 3 digit numbers with 2 digit numbers. For example; 345 x 92= First you will start with 2 by multiplying it by 5 then carry the 1 above the 4 then multiply the "2" with 4 then add the number on-top of the 4 which is 1 and it will give you 9. 4 x 2= 8+1=9. Then times the 2 by 3 which is 6. That is not your answer, yet. 690 plus the amount you get by multiplying 9 by every number, 5 then carry the number, 4 times 9, plus the number above it, then carry the 3 on top of the 3. Then add your total to 690 or what ever your equation is.
The smallest 5-digit number is 10000. To get the smallest 5-digit number, we put a 1 in the first column (since we can't start with a 0 or else we'd get a 4 digit number!), then put a 0 in every other column.
You start with 1 0r 0. one of them,......................I think............
You put the four digit number at the top of the three digit number and you do the same thing as you would do with a two digit number with a 3 digit number.
1We can not start a three digit number with 0, so 1 is the smallest digit.
The smallest 4 digit no is 1000. The smallest 2 digit no. is 10. Multiply these, you get 10,000. this is a 5 digit no. so the answer to your question is no. Multiplying one thousand by ten to get ten thousand is something you can do in your head in much less time than sending a question to wiki-answers. If you want to get better at math, start by always spending half a minute in thinking "is there an easy way to do this".
Start Select the three digit number two hundred forty two. End.
No. Three-digit numbers start with 100.
Here is the best way to do two digit times two digit multiplication. Start by multiplying the bottom right number by the top right number. Then put down the digit in the ones place and carry the number in the tens place (if you have one). Then multiply the bottom right number by the top left number. To that number, add the number of tens you carried(3x3=9+2=11). put that answer down next the first number, making it(if the first number you put down is 1, 111. Now onto the second digit.put a zero underneath one digit in the answer you got(111) Multiply the bottom left number by the top right number. Put the digit in the ones place (7, for example) down, next to the zero, and carry the number you had in the tens place. Multiply the bottom left number by the top left number. Place both of those numbers (if u have more than one) by the seven which is next to the zero. Add the numbers you have on the bottom. EXAMPLE: 111 + 370 ----------------------------- 481 ( this is your answer) Please note that the problem wasn't real... And was just an example for the steps of two digit multiplication.
13213
There is no such number. You can start with a different number and end with different ones.
2!, 3!, 4!, etc. carry:=0; % Start a multiply by n. for i:=1 to last do % Step along every digit. d:=digit[i]*n + carry; % The classic multiply. digit[i]:=d mod Base; % The low-order digit of the result. carry:=d div Base; % The carry to the next digit. next i; while carry > 0 % Store the carry in the big number. if last >= Limit then croak("Overflow!"); % If possible! last:=last + 1; % One more digit
It depends. If you start with a positive number, then multiply by a positive greater than one and the answer is greater; multiply by 1 and the answer is the same; multiply by a number between 0 and 1 and the answer is smaller; multiply by 0 and the answer is 0; multiply by a number less than 0 and the answer is negative.
In python, type the following into a document. NOTE: Sentences following a # symbol are comments, and are not necessary for the program to run. #!/usr/bin/python #This program takes a input from a user and reverses it. number = input("Type a number: ") #This takes input from a user. a = len(number) #This finds the length of the number reverse = "" #This sets the variable reverse to an empty string. for i in number: a = a-1 #The places in a string start from 0. The last value will be the length minus 1.reverse = reverse + number[a] #Makes the number's last digit the new string's first. print("The reverse of", number, "is", reverse + ".") #prints the resulting string. This program will take any sequence of characters and reverse them. The final value is a string, but if an integer is needed, one needs only to add the line reverse = int(reverse) above the print statement. However, this will stop the program from being able to reverse strings, as it is not possible to convert a string to an integer if it is not a number.
If multiplying 3 digit numbers with 2 digit numbers. For example; 345 x 92= First you will start with 2 by multiplying it by 5 then carry the 1 above the 4 then multiply the "2" with 4 then add the number on-top of the 4 which is 1 and it will give you 9. 4 x 2= 8+1=9. Then times the 2 by 3 which is 6. That is not your answer, yet. 690 plus the amount you get by multiplying 9 by every number, 5 then carry the number, 4 times 9, plus the number above it, then carry the 3 on top of the 3. Then add your total to 690 or what ever your equation is.