Q: How do you multiply out 5y 4t-2?

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y+5y

5y + 5y = 10y

4(t^2 - 3)

-3

Multiply the bottom equation by 5.

no site 4t2 profolio procure

5y-425 = -420

5y-3y = 2

Multiply the first by 3 and the second by -2

0

5y=25x 25x=5y -5y 25x-5y=0

-5y=-25

-8x-5y-45 is not an equation. An equation requires an equal sign in there somewhere. If you meant -8x-5y=45, then there are many ways to rewrite it, such as -(8x+5y)=45, or 8x+5y=-45, or 8x=-(45+5y), to name three. If you meant -8x-5y=-45, then you're probably looking for 8x+5y=45.

(5y - 1)(5y - 1) or (5y - 1)2

5y - 14y = -9y

5y - y = 4y

If: 4x = 5y Then: x = 5y/4

5y(1 - 13x)

3x/7 + 5y/14x = 3x*2x/(7*2x) + 5y/14x = (6x2 + 5y)/14x

-120

25y2 - 49w2 = (5y)2 - (7w)2 = (5y - 7w)(5y + 7w)

11x + 5y

10x-5y in slope form = 5

y/5 = y/6+9 Multiply all terms by 30 to eliminate the fractions 6y = 5y+ 270 Subtract 5y from both sides 6y-5y = 270 y = 270

To solve 4 ≥ 5y/-2 assuming normal algebraic rules regarding numbers and letters that are next to each other meaning multiply (and not as in a mixed number fraction): 4 ≥ 5y/-2 → 4 ≥ 5y/-2 (multiplying a fraction by a whole number → multiply numerator by the number) → 4 ≥ -5y/2 (make the denominator positive, so negate the numerator) → 8 ≥ -5y (multiply both sides by 2)* → 5y ≥ -8 (take the -5y and the 8 to the opposite sides, changing their signs) → y ≥ -8/5 (divide both sides by 5) Thus any value of y greater than or equal to -8/5 = -13/5 is a solution. * Multiplying (or dividing) both sides of an inequality by a negative number changes the direction of the inequality: greater than becomes less than and vice verse. By ensuring that the top of the negative "fraction" is the negative number and the bottom is positive, this change of inequality does not need to be remembered as a negative number is not used to multiply both sides.

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