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How would you put 5y equals 25 in standard form?
5y=25x 25x=5y -5y 25x-5y=0
What is 5y-3y?
5y-3y = 2
What is the answer for 5y equals 4735?
If: 5y = 4735 Then: y = 947
Factor this binomial 5y to the third - 125y?
-120
What are the soluition of these epautions 4x -5y -12 and -x 5y 18?
If you mean: 4x-5y = -12 and -x+5y =18 Then the solutions of the equations are: x = 2 and y = 4
Multiply y-5y 5?
y+5y
What is 8y 5y?
The expression "8y 5y" seems to be missing an operator. If you meant to add the two terms, it would be written as "8y + 5y," which simplifies to "13y." If you meant to multiply, it would be "8y * 5y," which simplifies to "40y²." Please clarify if you meant something different!
How do you factor 4t2 - 12?
4(t^2 - 3)
What is 5y plus 5y?
5y + 5y = 10y
What is y over 5 equal to y over 6 plus 9?
y/5 = y/6+9 Multiply all terms by 30 to eliminate the fractions 6y = 5y+ 270 Subtract 5y from both sides 6y-5y = 270 y = 270
Where can you play Lego mars mission?
no site 4t2 profolio procure
Let L be the line in R3 that consists of all scalar multiples of the vector -2 -1 2T Find the reflection of the vector v equal to 7 2 7T in the line L?
I'm not going to lie, I'm not 100% sure if I'm going to do this correctly. It's been a while since I've done something like this, so you may want to double check my answer. Also, the letter T in your question is really throwing me off, so I'm just going to give you two answers. The first answer will treat T as a variable, the second answer will ignore it completely. Both answers, however, use the following equation for the reflection of a vector about a line:RefL(v) = 2L(v ● L)/(L ● L) - vFor my first answer, I'll use the following vectors for Land v:L = -2i - j + 2Tk, andv = 7i + 2j + 7Tk,where i, j, and k are the unit vectors in the direction of the x, y, and z axes in R3, respectively.Thus,v ● L = -14 - 2 + 14T2 = 14T2 - 16.L ● L = 4 + 1 + 4T2 = 4T2 + 5.Therefore, 2L(v ● L)/(L ● L) =2L(14T2 - 16)/(4T2 + 5) = L(28T2 - 32)/(4T2 + 5) =-8(7T2 - 8)/(4T2 + 5)i - 4(7T2 - 8)/(4T2 + 5)j + 8T(7T2 - 8)/(4T2 + 5)k.Let A = 2L(v ● L)/(L ● L).(A - v)i = [-8(7T2 - 8)/(4T2 + 5) - 7(4T2 + 5)/(4T2 + 5)]i =(-56T2 + 64 - 28T2 - 35)/(4T2 + 5)i = (-84T2 + 29)/(4T2 + 5)i.(A - v)j = [-4(7T2 - 8)/(4T2 + 5) - 2(4T2 + 5)/(4T2 + 5)]j =(-28T2 + 32 - 8T2 - 10)/(4T2 + 5)j = (-36T2 + 22)/(4T2 + 5)j.(A - v)k = [8T(7T2 - 8)/(4T2 + 5) - 7T(4T2 + 5)/(4T2 + 5)]k =(56T3 - 64T - 28T3 - 35T)/(4T2 + 5)k = (28T3 - 99T)/(4T2 + 5)k.Let b = 1/(4T2 + 5), thenRefL(v) = b[(-84T2 + 29)i + (-36T2 + 22)j + (28T3 - 99T)k]That expression for RefL(v) looks pretty ugly, so I'm going to do the problem again, this time without the variable T.L = -2i - j + 2k, andv = 7i + 2j + 7k.v ● L = -14 - 2 + 14 = -2L ● L = 4 + 1 + 4 = 9Therefore, 2L(v ● L)/(L ● L) =2L(-2/9) = L(-4/9) =(8/9)i + (4/9)j - (8/9)k.RefL(v) = 2L(v ● L)/(L ● L) - v = (8/9)i + (4/9)j - (8/9)k - 7i - 2j - 7k =-(55/9)i - (14/9)j - (71/9)k.While this expression does look much nicer, I'm not sure if it's right. So, like I recommended above, please double check my work!
-4x plus 5y equals -6 -6x - y equals 5?
Multiply the first by 3 and the second by -2
How would you put 5y equals 25 in standard form?
5y=25x 25x=5y -5y 25x-5y=0
What is 52-5y?
What is 52-5y 52 = 5Y 52 = Y 5 10.4 =Y
What is 5y- 5y?
0
What expression is equivalent to -(-5y-2)?
-3
