x ALWAYS = 1
Given 20 and 50%, multiply 20 by 0.5, which equals 10. Given 70 and 30%, multiply 70 by 0.3, which equals 21. Or if you prefer, given 20 and 50%, multiply 2 by 5, which equals 10. Or if you prefer, given 70 and 30%, multiply 7 by 3, which equals 21.
Multiply the given number as many times as the problem indicates. example: 5^3 is 5 x 5 x 5, which equals 125.
No! To get the solution number of unknown variables must be equal to the number of equations. [For example, In this case, two variables (x and y) are involved but only one equation is given. so, we need one more equation having same two variables to get the solution.] If there is no other equation then value of any one of the variables involved (x or y) must be given to ind the value of the other unknown variable.
Multiply the number by 100%. 100% equals 1, and it is always OK to multiply a number or variable by 1 because that doesn't change its value. To multiply by 100%, shift the decimal point two places to the right and insert the % symbol. For example, 1.2 = 120%.
It equals -36. To solve replace x with -6, because it is the value given in the problem and then just multiply. 6(-6)= -36.
yz means to multiply y times z. So you just replace the values, and do the multiplication.
Multiply the decimal by 100 as for example 0.75 = 75%
Solving for two unknown variables (x and y) requires two independent equations. You have given only one.
To get to answer of 1 in a multiplication problem such as this you multiply the given number by it's inverse. In your example: 7069 * 1/7069 = 1
explain how to evaluate an algebraic expression for given variables. how would we evaluate the expression "3x-4y+9" when x=2and y=5?
The two numbers that satisfy the given conditions are 4 and 1. When you add 4 and 1, you get 5. When you multiply 4 and 1, you get 4. The two numbers are 4 and 1.
That depends what data you are given. If you have linear measurements, you'll somehow have to multiply them. For example, for a rectangle, you multiply length x width; for a circle (if you know the radius) you multiply pi x radius x radius, etc.