0
Add your answer:
Earn +20 pts
How do you answer 2x plus 6y equals 32 and 5x-2y equals 12 using subtitution?
First, change 2x+6y=32 to x+3y=16. Then solve for x, which is x=-3y+16. Then substitute -3y+16 as x into 5x-2y=12 and solve for y. 5(-3y+16)-2y=12 -15y+80-2y=12 -17y+80=12 -17y=-68 y=4 Then substitute 4 as y in either equation to solve for x. 5x-2(4)=12 5x-8=12 5x=20 x=4 The answer is x=4 and y=4, or (4,4)
X plus 2y equals -1 5x - 4y equals 16?
x+2y = -1 and 5x-4y = 16 Solving the simultaneous equations gives: x = 2 and y = -1.5
How do you solve 5x-19 equals 16?
5x-19 = 16 5x = 16+19 5x = 35 x = 7
Solve the following system of equations 5x plus y equals -9 -5x plus 2y equals 0?
x = -1.2, y = -3
Solve for X and Y using the addition method 3X plus 2Y equals 4 X-Y equals 8?
3x + 2y = 4; 2x - 2y = 16 Add; 5x = 20 so x = 4 and y is therefore -4
How do you answer 2x plus 6y equals 32 and 5x-2y equals 12 using subtitution?
First, change 2x+6y=32 to x+3y=16. Then solve for x, which is x=-3y+16. Then substitute -3y+16 as x into 5x-2y=12 and solve for y. 5(-3y+16)-2y=12 -15y+80-2y=12 -17y+80=12 -17y=-68 y=4 Then substitute 4 as y in either equation to solve for x. 5x-2(4)=12 5x-8=12 5x=20 x=4 The answer is x=4 and y=4, or (4,4)
X plus 2y equals -1 5x - 4y equals 16?
x+2y = -1 and 5x-4y = 16 Solving the simultaneous equations gives: x = 2 and y = -1.5
How do you solve 5x-19 equals 16?
5x-19 = 16 5x = 16+19 5x = 35 x = 7
Solve the following system of equations 5x plus y equals -9 -5x plus 2y equals 0?
x = -1.2, y = -3
Solve for X and Y using the addition method 3X plus 2Y equals 4 X-Y equals 8?
3x + 2y = 4; 2x - 2y = 16 Add; 5x = 20 so x = 4 and y is therefore -4
Solve using susbstitution method X-5y equals -54 and 2y-5x equals 63?
8840-026
How do I solve 5x plus 2y equals 20?
If as a straight line equation: 5x+2y = 20 then y = -2.5x+10 whereas -2.5 is the slope and 10 is the y intercept
How can i solve 5x - 2y 10?
if you mean 5x -2y = 10 then y = 2.5x -5
Solve the following system of equations express your answer as an ordered pair 2x plus 5y equals 16 and -5x minus 2y equals 2?
The solutions are: x = -2 and y = 4
Solve the system using substitution 5x-y equals 5 diveded by5x-3y equals 15?
5x - y = 55x - 3y = 15from the first equation:5x = 5 + y , substitute it in the second equation:5 + y - 3y = 155 -2y = 15-2y = 15 - 5-2y = 10y = -5Now,solve for x :5x = 5 +y5x = 5 -5 = zerox = zero
3x plus 2y equals 20 and 5x-2y equals 1?
3x+2y=20 5x-2y=1 (3x+2y) + (5x-2y)= 20+1 3x+5x= 21....... 8x=21.........x=2 5/8 Subsitute x=3(2 5/8)+ 2y=20........... 7 7/8 +2y=20.........2y= 20- 7 7/8....... y=6 1/16
Solve the system 5x plus 2y equals 1?
To solve for two unknowns (x and y) it is necessary to have two independent equations.
