10-4
1 M is equal to 1000 mM. Calculating molarity is important in biochemical and molecular experiments. Normally 10 X or 20X stock solution are prepared from which the working solutions are diluted as per the need of the concentration (in mM)
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Dilute a measured volume of the 100 mM solution with 19 times its own volume of pure water to produce a 5mM solution.
10 mm = 1 cm so 545 mm = 545/10 = 54.5 cm. Simple! 10 mm = 1 cm so 545 mm = 545/10 = 54.5 cm. Simple! 10 mm = 1 cm so 545 mm = 545/10 = 54.5 cm. Simple! 10 mm = 1 cm so 545 mm = 545/10 = 54.5 cm. Simple!
1 cm = 10 mm 7 cm = 70 mm
pl. suggest how to prepare 50 sulphuric acid
I really dont know people
for prepare 1mM DPPH radical solution: DPPH Molecular weight: C18H12N5O6 = 394g DPPH 1mM = 394/1000= 0.394g/L
A water solution containing 50 mM tris(hydroxymethyl)aminomethane and 150 mM sodium chloride has a pH of 7,6.
Preparation of 100 mM H₂O₂ Measure out 10 mL of 30% hydrogen peroxide (H₂O₂). Dilute the 10 mL of 30% H₂O₂ with 90 mL of deionized water. The resulting solution is roughly 100 mM H₂O₂.
I don't know how to make the solution below. Low salt buffer: 10 mM phosphate buffer, 10 mM NaCl, pH 7.4. Could you tell me the method in detail?
the mass of the EDTA used to prepare 1L oi solution is 18.612g. The formula mass is 372.24 g/mol. Therefore concentration of the 50x solution is: 18.612 g 1 mol ----------- x --------- = 0.050000 mol/L = 50.000 mM 1L 372.24 g
1 M is equal to 1000 mM. Calculating molarity is important in biochemical and molecular experiments. Normally 10 X or 20X stock solution are prepared from which the working solutions are diluted as per the need of the concentration (in mM)
You have to dilute the 10 mM NaCl 100X, 33,333X and 10X (X means "times") e.g. 100X: mix 10 ml of 10 mM Nacl with 990 ml of water (= 0,1 mM) 33,333X: mix 30 ml of 10 mM NaCl with 970 ml of water (= 0,3 mM) 10X: mix 100 ml of 10 mM NaCl with 900 ml of water (= 1 mM)
1 cm = 10 mm 1 cm = 1 x 10-2 m solution : 4 cm x ((10 mm) / (1 cm)) cancel out the unit for cm : 4 cm x ((10 mm) / (1 cm) = 40 mm THE ANSWER IS 40 mm
[1 mL*10 mM + 4 mL*(50*2 mM Cl-) ] mmolCl- in [1+4] mL total solutionThis is 410 (mmol Cl-) / 5 (mL) = 82 mM Cl-
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