take 15ml od dettol solution and add into 285 ml of water . then you wll get 5% of dettol solution
ask your teacher.
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
160 g (solution) - [5/100*160] g (solute) = 152 g (solvent) water
what is the composition of dextrose 5%
Check what it is dissolved in first and use the same solvent for dilution. If you want to make a litre of 10% for instance, You want to dilute it 10 in 26 parts or 5 in 13. So 1 litre /13*5 is 384.6ml of 26% ammonia, and dilute to 1 litre with solvent
ask your teacher.
first calculate vd * CD =Vc * Cc Vc=50 * 2 / 5 =20ml
See the two Related Questions to the left for the answer.The first is how to prepare a solution starting with a solid substance (and dissolving it). The second question is how to prepare a solution by diluting another solution.
125 ml 500(ml) * 0.05 = 25 25 / 0.20 = 125
true
Take 5% of 350g = 17.5 g sugarand add 350g -17.5g = 332.5 g solvent (water, most likely, this is 333 mL)
Double the amount of solvent.
get 5%
You dillute it with some more of the same solvent used for the 6 percent solution - pressumably water.
50liters
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
molarity of 5% NaCl solution would be 1.25M.