first calculate
vd * CD =Vc * Cc Vc=50 * 2 / 5 =20ml
Unfortunately sugar is an imprecise term. It is better to specify glucose (usually means dextrose) or sucrose or fructose etc.A 5 percent solution of one of these sugars would contain 5 grams weight dissolved in 100mL of water (or could be another solvent).Read more: What_does_a_5_percent_sugar_solution_mean
I hope you don't work in a hospital, and I also hope you have passed 7th grade.But, 5% of a 1 L (1000 g) solution would be 50 grams.
10 mg/ml stock solution
Normal Saline Solution in 5% Dextrose or D5NSS is a hypertonic solution. It can be used for the temporary treatment of shock if plasma expanders are not available. However, do not administer this IV for clients with cardiac or renal conditions.
It would flow toward the weaker solution. The intent of osmosis is to gain equilibrium, so the 15 percent solution would gain sugar content until, if you allowed the osmosis to go to completion, the two solutions had the same amount of sugar in them. "Going to completion" doesn't necessarily mean 20 percent concentration on both sides. If you were to make a gallon bag out of dialysis membrane, fill it with 15 percent solution and put a stirrer in it, then drop it into a 25,000-gallon reaction vessel full of 25 percent solution with a stirrer in it, you might wind up with 24.9999999999 percent sugar solution in both bags.
pharmacist
See the two Related Questions to the left for the answer.The first is how to prepare a solution starting with a solid substance (and dissolving it). The second question is how to prepare a solution by diluting another solution.
Dextrose is a solid so it doesn't really have a pH until it is in solution. Once it is in solution, it would depend on what the solvent was and the concentration of the dextrose. So it could range greatly, but most are kept around 6.4.
To prepare 6 nM ammonium hydroxide a 30 percent solution you need to know the volume of the 30 percent solution that you have and the volume of 6nM solution you would like to make. Then use the following formula: C1V1 = C2V2 where C = concentration in moles/Liter and V = volume in liters.
You would dissolve 1 part HNO3 into 99 parts of your solvent.
Diluted Ammonia solution can be prepared by diluted strong ammonia solution with the appropriate quantity of purified water.
Unfortunately sugar is an imprecise term. It is better to specify glucose (usually means dextrose) or sucrose or fructose etc.A 5 percent solution of one of these sugars would contain 5 grams weight dissolved in 100mL of water (or could be another solvent).Read more: What_does_a_5_percent_sugar_solution_mean
I hope you don't work in a hospital, and I also hope you have passed 7th grade.But, 5% of a 1 L (1000 g) solution would be 50 grams.
Unfortunately sugar is an imprecise term. It is better to specify glucose (usually means dextrose) or sucrose or fructose etc. A 5 percent solution of one of these sugars would contain 5 grams weight dissolved in 100mL of water (or could be another solvent).
If the percents given are by weight or mass, this is very straightforward: The ratio between the desired percentage and the initial percentage is 1/50. Therefore, a given mass of initial solution must be diluted to 50 times its original mass to obtain the desired lower concentration, or in other words, 49 parts of diluent must be mixed with each part of initial solution. If the percents involve volume measurements, it would be necessary to take into account and change in density occasioned by the dilution.
10 mg/ml stock solution
You would wan to dilute the trisodium citrate in distilled water to create a 1% solution. So if you wanted 100mL of solution, you would mix 1mL of trisodium citrate with 99mL of distilled sterile water.