Best Answer

Multiply both sides by sin(1-cos) and you lose the denominators and get (sin squared) minus 1+cos times 1-cos.

Then multiply out (i.e. expand) 1+cos times 1-cos, which will of course give the difference of two squares: 1 - (cos squared). (because the cross terms cancel out.)

(This is diff of 2 squares because 1 is the square of 1.)

And so you get (sin squared) - (1 - (cos squared)) = (sin squared) + (cos squared) - 1.

Then from basic trig we know that (sin squared) + (cos squared) = 1, so this is 0.

Q: How do you prove that the sin over one minus the cosine minus one plus the cosine over the sine equals zero?

Write your answer...

Submit

Still have questions?

Related questions

Secant is 1 over cosine and cosine 0 equals 1.

Unfortunately, 2 over 2 minus 1 equals 5 over 6 is just a wrong answer! If it is 2 over 2, minus 1, the answer is that it equals zero. If it is 2, over 2 minus 1, the answer is that it equals 2.

A way of remembering how to compute the sine, cosine, and tangent of an angle. SOH stands for Sine equals Opposite over Hypotenuse. CAH stands for Cosine equals Adjacent over Hypotenuse. TOA stands for Tangent equals Opposite over Adjacent.

Approx 44.4 degrees.

5 over 8

6/11 minus 5/6 equals -19/66

2/5 minus 4/9 equals -2/45

The answer is 8/36 minus 3/14 equals 1/126

4/9 minus 3/4 equals -11/36

2 minus 5/2 equals -1/2

3/2 minus 2 equals -1/2

...7 over 36?