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The area under an acceleration-time graph is equal to the object's velocity (not change in velocity).
By using the distance, speed, and acceleration, to show on the graph the constant speed of each car
A period of constant positive acceleration;a second period of zero acceleration; a third period of constant negative acceleration.
acceleration.
The answer depends on what is plotted on the graph and what is happening with the acceleration then.
This depends on what the graph represents. If it is a graph of velocity on the vertical and time on the horizontal, then if acceleration is at a constant rate, the graph will be a straight line with positive slope (pointing 'up'). If acceleration stops, then the graph will be a horizontal line (zero acceleration or deceleration). If it is deceleration (negative acceleration), then the graph will have negative slope (pointing down).
Acceleration is negative when the object is moving in the opposite direction. on a graph the line would be in the negative quadrant.
Acceleration is negative.
On a graph of acceleration vs. time, during deceleration the line is below zero. On a graph of speed vs. time, during deceleration the line has a negative slope (sloping downward from left to right).
acceleration is the slope of the v t graph... so the acceleration is constant and negative. In other words, the object is slowing down at a constant rate.
True
The acceleration of an object.
The answer depends on whether the graph is that of speed v time or distance v time.
The area under an acceleration-time graph is equal to the object's velocity (not change in velocity).
By using the distance, speed, and acceleration, to show on the graph the constant speed of each car
The answer depends on what the graph is meant to show. The first step would be to read the axis labels.
A period of constant positive acceleration;a second period of zero acceleration; a third period of constant negative acceleration.