0.5 * sqrt(112)
this is pretty much all there is to it.
75 goes into 300 4 times. A half of 300 is 150. A half of that is 75. A half of a half is a quarter.
The equation is AREA = ONE HALF times BASE times HEIGHT The BASE is the length of the bottom line. The HEIGHT is the 'straight up' distance from the (horizontal) bottom line to the tip. And ONE HALF is, well, one half. So if your triangle had a bottom line of length 5 ft, and a height of 7 ft, the area would be 1/2 times 5 times 7, that is, 35/2 or 17.5 square feet.
At the level asked there is no difference. As the size goes up there is a big difference... Two miles square would be 2x2 = four square miles.
4 and a half
One quarter square mile.
1/2*b*h one half times base times height
The quadratic equation of the square is probably x2-5x+6.25 = 0 because its discriminant is equal to zero giving the equation equal roots of x = 5/2 and x = 5/2
3 goes into 6 two times, so 6 goes into 3 one half times.
Use the formula area = pi times radius2 to get the area. The radius is half the diameter. A foot is 12 inches, a square foot is 144 square inches.Use the formula area = pi times radius2 to get the area. The radius is half the diameter. A foot is 12 inches, a square foot is 144 square inches.Use the formula area = pi times radius2 to get the area. The radius is half the diameter. A foot is 12 inches, a square foot is 144 square inches.Use the formula area = pi times radius2 to get the area. The radius is half the diameter. A foot is 12 inches, a square foot is 144 square inches.
Brahmagupta gave the solution of the general linear equation in chapter eighteen of Brahmasphutasiddhanta,18.43 The difference between rupas, when inverted and divided by the difference of the unknowns, is the unknown in the equation. The rupas are [subtracted on the side] below that from which the square and the unknown are to be subtracted.[4]Which is a solution equivalent to , where rupasrepresents constants. He further gave two equivalent solutions to the general quadratic equation,18.44. Diminish by the middle [number] the square-root of the rupas multiplied by four times the square and increased by the square of the middle [number]; divide the remainder by twice the square. [The result is] the middle [number].18.45. Whatever is the square-root of the rupasmultiplied by the square [and] increased by the square of half the unknown, diminish that by half the unknown [and] divide [the remainder] by its square. [The result is] the unknown.[4]Which are, respectively, solutions equivalent to,andHe went on to solve systems of simultaneous indeterminate equations stating that the desired variable must first be isolated, and then the equation must be divided by the desired variable's coefficient
8 goes into 412, 51 and a half times.
One half its base times its height, or 1/2 b*h.