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The quadratic equation of the square is probably x2-5x+6.25 = 0 because its discriminant is equal to zero giving the equation equal roots of x = 5/2 and x = 5/2
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The length of a rectangle is 1 more than twice its width and the area of the rectangle is 45 what are the dimensions of the rectangle?
Assign the rectangle a width 'x'. From the data in the problem the height is then '2x+1'. Multiplying the two together gives the area of the rectangle, which we know to be 45. In equation for this is: x(2x+1) = 45 or 2x^2 + x = 45. The roots of this equation can then be found either through the quadratic equation or a calculator solver (I used the solver because I'm lazy) and the answers are x = -5 and x= 4.5. The rectangle has a width of 4.5 and a height of 10.
The formula for the perimeter of a rectangle is P equals 2l plus 2w where l is the lengty and w is the width a rectangle has a permeter of 24 inches find its dimensions if its length is 3 in greater?
Oh, what a happy little problem we have here! If the perimeter of the rectangle is 24 inches, we can use the formula P = 2l + 2w to find its dimensions. Since the length is 3 inches greater than the width, we can set up the equation 24 = 2(l + 3) + 2l and solve for l and w. With a little bit of math magic, we'll find that the dimensions of this lovely rectangle are 9 inches in length and 6 inches in width.
How do you calculate the dimensions of a rectangle if you know the perimeter and the length?
A rectangle by definition has two pairs of sides with equal length. Since perimeter equals the length of all the sides. The equation for the perimeter of a rectangle could be thought of as: 2L + 2W = P Where L represents the length of one side of the rectangle and W represents the length of the adjacent (next to) side of the rectangle. If you know the length of one side and the perimeter, plug those values in as L and P and then solve for W. That will give you L and W which are the dimensions of the rectangle.
The length of a rectangle is 1 yard more than twice its width and the area of the rectangle is 66 squared Find the dimensions of the rectangle?
Let the length be 2x+1 and the width be x: (2x+1)*x = 66 square yards 2x2+x = 66 2x2+x-66 = 0 Solving the above equation by means of the quadratic equation formula will give: x = -6 or x = 5.5, so x must be the latter because dimensions can't be negative. Therefore: length = 12 yards and width = 5.5 yards Check: 12*5.5 = 66 square yards
The area of a rectangle is 243 cm2 The length is three times greater than the width What are the dimensions?
Let the length be 3x and the width be x: 3x*x = 243 3x2 = 243 Divide both sides by 3: x2 = 81 Square root both sides: x = 9 Therefore: length = 27 cm and width = 9 cm
