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The quadratic equation of the square is probably x2-5x+6.25 = 0 because its discriminant is equal to zero giving the equation equal roots of x = 5/2 and x = 5/2
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The length of a rectangle is 1 more than twice its width and the area of the rectangle is 45 what are the dimensions of the rectangle?
Assign the rectangle a width 'x'. From the data in the problem the height is then '2x+1'. Multiplying the two together gives the area of the rectangle, which we know to be 45. In equation for this is: x(2x+1) = 45 or 2x^2 + x = 45. The roots of this equation can then be found either through the quadratic equation or a calculator solver (I used the solver because I'm lazy) and the answers are x = -5 and x= 4.5. The rectangle has a width of 4.5 and a height of 10.
The formula for the perimeter of a rectangle is P equals 2l plus 2w where l is the lengty and w is the width a rectangle has a permeter of 24 inches find its dimensions if its length is 3 in greater?
Oh, what a happy little problem we have here! If the perimeter of the rectangle is 24 inches, we can use the formula P = 2l + 2w to find its dimensions. Since the length is 3 inches greater than the width, we can set up the equation 24 = 2(l + 3) + 2l and solve for l and w. With a little bit of math magic, we'll find that the dimensions of this lovely rectangle are 9 inches in length and 6 inches in width.
How do you calculate the dimensions of a rectangle if you know the perimeter and the length?
A rectangle by definition has two pairs of sides with equal length. Since perimeter equals the length of all the sides. The equation for the perimeter of a rectangle could be thought of as: 2L + 2W = P Where L represents the length of one side of the rectangle and W represents the length of the adjacent (next to) side of the rectangle. If you know the length of one side and the perimeter, plug those values in as L and P and then solve for W. That will give you L and W which are the dimensions of the rectangle.
The length of a rectangle is 1 yard more than twice its width and the area of the rectangle is 66 squared Find the dimensions of the rectangle?
Let the length be 2x+1 and the width be x: (2x+1)*x = 66 square yards 2x2+x = 66 2x2+x-66 = 0 Solving the above equation by means of the quadratic equation formula will give: x = -6 or x = 5.5, so x must be the latter because dimensions can't be negative. Therefore: length = 12 yards and width = 5.5 yards Check: 12*5.5 = 66 square yards
The area of a rectangle is 243 cm2 The length is three times greater than the width What are the dimensions?
Let the length be 3x and the width be x: 3x*x = 243 3x2 = 243 Divide both sides by 3: x2 = 81 Square root both sides: x = 9 Therefore: length = 27 cm and width = 9 cm
You are interested in the dimensions of a certain square A rectangle has length triple the side of this square and width two units less than the side of this square Which equation describes this situ?
x^2=3x(x-2)
The base of a rectangle is 4 more than the height the area of the rectangle is 15 square inches what are the dimensions of the rectangle?
4,3Improved Answer:-The dimensions work out as: 2.358898944 and 6.358898944 inches using the quadratic equation formula
What are the dimensions of a rectangle if the area is 100?
To find the dimensions of a rectangle with an area of 100, you can use the formula for the area, which is length × width = area. Therefore, if one side is denoted as length ( l ) and the other as width ( w ), the equation becomes ( l \times w = 100 ). There are many possible pairs of dimensions that satisfy this equation, such as 10 and 10, 25 and 4, or 50 and 2. The dimensions can vary as long as their product equals 100.
What is the dimension of the rectangle when the length is 7 cm more than its width and the area is 60cm squared?
Let the width of the rectangle be ( w ) cm. Then, the length can be expressed as ( w + 7 ) cm. The area of the rectangle is given by the equation ( w(w + 7) = 60 ). Solving this quadratic equation, we find that the dimensions of the rectangle are a width of 3 cm and a length of 10 cm.
What is first length or width in this equation 22 x 44?
If that's for a rectangle, the larger of the two dimensions is usually called the "length", the other one, "width".
The length of a rectangle is 1 more than twice its width and the area of the rectangle is 45 what are the dimensions of the rectangle?
Assign the rectangle a width 'x'. From the data in the problem the height is then '2x+1'. Multiplying the two together gives the area of the rectangle, which we know to be 45. In equation for this is: x(2x+1) = 45 or 2x^2 + x = 45. The roots of this equation can then be found either through the quadratic equation or a calculator solver (I used the solver because I'm lazy) and the answers are x = -5 and x= 4.5. The rectangle has a width of 4.5 and a height of 10.
How do you turn this into an equation The perimeter of a rectangle is 126cm The rectangle is twice as long as it is wide What are the dimensions?
the formula for the perimeter of a rectangle is p = 2W + 2L, where L is the length and W is the width, so your first equation is 126 = 2W + 2L"twice as long as it is wide" means that the length L is 2 times the width W, so your second equation is L = 2WIn order to solve for the dimensions, you can substitute L for 2W in the first equation to get:126 = L + 2L126 = 3LL = 126/3L = 42and because L = 2W:42 = 2WW = 42/2W = 21
What are the dimensions of a rectangle if the length is 5 feet longer than four times th width?
Anything. No area is specified, so the dimensions are w*(4w+5) This equation lacks any value to define w.
The formula for the perimeter of a rectangle is P equals 2l plus 2w where l is the lengty and w is the width a rectangle has a permeter of 24 inches find its dimensions if its length is 3 in greater?
Oh, what a happy little problem we have here! If the perimeter of the rectangle is 24 inches, we can use the formula P = 2l + 2w to find its dimensions. Since the length is 3 inches greater than the width, we can set up the equation 24 = 2(l + 3) + 2l and solve for l and w. With a little bit of math magic, we'll find that the dimensions of this lovely rectangle are 9 inches in length and 6 inches in width.
How do you calculate the dimensions of a rectangle if you know the perimeter and the length?
A rectangle by definition has two pairs of sides with equal length. Since perimeter equals the length of all the sides. The equation for the perimeter of a rectangle could be thought of as: 2L + 2W = P Where L represents the length of one side of the rectangle and W represents the length of the adjacent (next to) side of the rectangle. If you know the length of one side and the perimeter, plug those values in as L and P and then solve for W. That will give you L and W which are the dimensions of the rectangle.
What is the answer of equation that length multiplied by width of a rectangle?
area of the rectangle..
What is the base equation for calculating the area of a rectangle?
The base equation for calculating the area of a rectangle is length multiplied by width.
