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The quadratic equation of the square is probably x2-5x+6.25 = 0 because its discriminant is equal to zero giving the equation equal roots of x = 5/2 and x = 5/2
What else can I help you with?
The length of a rectangle is 1 more than twice its width and the area of the rectangle is 45 what are the dimensions of the rectangle?
Assign the rectangle a width 'x'. From the data in the problem the height is then '2x+1'. Multiplying the two together gives the area of the rectangle, which we know to be 45. In equation for this is: x(2x+1) = 45 or 2x^2 + x = 45. The roots of this equation can then be found either through the quadratic equation or a calculator solver (I used the solver because I'm lazy) and the answers are x = -5 and x= 4.5. The rectangle has a width of 4.5 and a height of 10.
The formula for the perimeter of a rectangle is P equals 2l plus 2w where l is the lengty and w is the width a rectangle has a permeter of 24 inches find its dimensions if its length is 3 in greater?
Oh, what a happy little problem we have here! If the perimeter of the rectangle is 24 inches, we can use the formula P = 2l + 2w to find its dimensions. Since the length is 3 inches greater than the width, we can set up the equation 24 = 2(l + 3) + 2l and solve for l and w. With a little bit of math magic, we'll find that the dimensions of this lovely rectangle are 9 inches in length and 6 inches in width.
How do you calculate the dimensions of a rectangle if you know the perimeter and the length?
A rectangle by definition has two pairs of sides with equal length. Since perimeter equals the length of all the sides. The equation for the perimeter of a rectangle could be thought of as: 2L + 2W = P Where L represents the length of one side of the rectangle and W represents the length of the adjacent (next to) side of the rectangle. If you know the length of one side and the perimeter, plug those values in as L and P and then solve for W. That will give you L and W which are the dimensions of the rectangle.
The length of a rectangle is 1 yard more than twice its width and the area of the rectangle is 66 squared Find the dimensions of the rectangle?
Let the length be 2x+1 and the width be x: (2x+1)*x = 66 square yards 2x2+x = 66 2x2+x-66 = 0 Solving the above equation by means of the quadratic equation formula will give: x = -6 or x = 5.5, so x must be the latter because dimensions can't be negative. Therefore: length = 12 yards and width = 5.5 yards Check: 12*5.5 = 66 square yards
The area of a rectangle is 243 cm2 The length is three times greater than the width What are the dimensions?
Let the length be 3x and the width be x: 3x*x = 243 3x2 = 243 Divide both sides by 3: x2 = 81 Square root both sides: x = 9 Therefore: length = 27 cm and width = 9 cm
You are interested in the dimensions of a certain square A rectangle has length triple the side of this square and width two units less than the side of this square Which equation describes this situ?
x^2=3x(x-2)
The base of a rectangle is 4 more than the height the area of the rectangle is 15 square inches what are the dimensions of the rectangle?
4,3Improved Answer:-The dimensions work out as: 2.358898944 and 6.358898944 inches using the quadratic equation formula
What is first length or width in this equation 22 x 44?
If that's for a rectangle, the larger of the two dimensions is usually called the "length", the other one, "width".
The length of a rectangle is 1 more than twice its width and the area of the rectangle is 45 what are the dimensions of the rectangle?
Assign the rectangle a width 'x'. From the data in the problem the height is then '2x+1'. Multiplying the two together gives the area of the rectangle, which we know to be 45. In equation for this is: x(2x+1) = 45 or 2x^2 + x = 45. The roots of this equation can then be found either through the quadratic equation or a calculator solver (I used the solver because I'm lazy) and the answers are x = -5 and x= 4.5. The rectangle has a width of 4.5 and a height of 10.
How do you turn this into an equation The perimeter of a rectangle is 126cm The rectangle is twice as long as it is wide What are the dimensions?
the formula for the perimeter of a rectangle is p = 2W + 2L, where L is the length and W is the width, so your first equation is 126 = 2W + 2L"twice as long as it is wide" means that the length L is 2 times the width W, so your second equation is L = 2WIn order to solve for the dimensions, you can substitute L for 2W in the first equation to get:126 = L + 2L126 = 3LL = 126/3L = 42and because L = 2W:42 = 2WW = 42/2W = 21
What are the dimensions of a rectangle if the length is 5 feet longer than four times th width?
Anything. No area is specified, so the dimensions are w*(4w+5) This equation lacks any value to define w.
The formula for the perimeter of a rectangle is P equals 2l plus 2w where l is the lengty and w is the width a rectangle has a permeter of 24 inches find its dimensions if its length is 3 in greater?
Oh, what a happy little problem we have here! If the perimeter of the rectangle is 24 inches, we can use the formula P = 2l + 2w to find its dimensions. Since the length is 3 inches greater than the width, we can set up the equation 24 = 2(l + 3) + 2l and solve for l and w. With a little bit of math magic, we'll find that the dimensions of this lovely rectangle are 9 inches in length and 6 inches in width.
How do you calculate the dimensions of a rectangle if you know the perimeter and the length?
A rectangle by definition has two pairs of sides with equal length. Since perimeter equals the length of all the sides. The equation for the perimeter of a rectangle could be thought of as: 2L + 2W = P Where L represents the length of one side of the rectangle and W represents the length of the adjacent (next to) side of the rectangle. If you know the length of one side and the perimeter, plug those values in as L and P and then solve for W. That will give you L and W which are the dimensions of the rectangle.
What is the answer of equation that length multiplied by width of a rectangle?
area of the rectangle..
What is the base equation for calculating the area of a rectangle?
The base equation for calculating the area of a rectangle is length multiplied by width.
A rectangle is 3 times longer than it is wide The perimeter is 44 cm Find the dimensions of the rectangle?
Let x represent width. Using the formula 3x(x)=44cm, the equation is complete when x = 3.82. This means that the rectangle is 3.82 cm wide, and 11.46 cm long.
How do you draw a rectangle with area 24 cm2 and perimeter 28 cm?
To draw a rectangle with an area of 24 cm² and a perimeter of 28 cm, we need to find the dimensions that satisfy both conditions. Let the length be ( l ) and the width be ( w ). The area equation is ( l \times w = 24 ) and the perimeter equation is ( 2(l + w) = 28 ). From the perimeter, we get ( l + w = 14 ). Solving these two equations simultaneously, we can express ( w ) as ( w = 14 - l ) and substitute it into the area equation to find ( l ) and ( w ) are 6 cm and 4 cm, respectively. Thus, the rectangle can be drawn with dimensions 6 cm by 4 cm.
