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Use the FOIL method.
(4x^3 - 4)(x^2-25)
4x^3*x^2=4x^5
-4*x^2=-4x^2
4x^3*-25=-100x^3
-4*-25=100
4x^5-100x^3-4x^2+100
Factor out a 4 to simplify
4(x^5-25x^3-x^2+25)
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∙ 13y ago
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How do you factor 4x3-8x?
4x(x2 - 2)
X2 plus 1 divided by 2x4 plus 4x3 -x2 plus 4x-3?
You can work this out with long division, by checking to see if (x2 - 1) is a factor of (2x4 + 4x3 - x2 + 4x - 3). It is. Unfortunately, the WikiAnswers system is somewhat limited in depicting things such as long division, so we won't be able to represent it here. In short though, (2x4 + 4x3 - x2 + 4x - 3) / (x2 + 1) is equal to 2x2 + 4x - 3. which means that: (x2 + 1) / (2x4 + 4x3 - x2 + 4x - 3) = (x2 + 1) / (x2 + 1)(2x2 + 4x - 3) = 1 / (2x2 + 4x - 3)
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X2+Y3+15 All you can do is simplify it.
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the awnser is 18.. i think..
