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What else can I help you with?
Expand and simplify Brackets x-6 Brackets Brackets x plus 4 Brackets?
(x - 6) (x + 4) = x2 - 2x - 24
Simplify (1x2-2x plus 4) plus (2x plus 1)-(x2 plus 5)?
To simplify the expression ((1x^2 - 2x + 4) + (2x + 1) - (x^2 + 5)), first combine like terms. The (x^2) terms give (1x^2 - 1x^2 = 0). The (x) terms yield (-2x + 2x = 0), and the constant terms combine to (4 + 1 - 5 = 0). Thus, the simplified expression is (0).
X3 plus x2 minus 6x plus 4?
x3 + x2 - 6x + 4 = (x - 1)(x2 + 2x - 4)
X2 plus 2x plus 4?
x= -3
What is x2-2x plus 4 plus 2x plus 1-x62 plus 5?
I'm answering this based on the way you wrote it. If you meant something different, please substitute words where necessary. x2-2x+4+2x+1-x62+5=2x-2x+4+2x+1-62x+5=-60x+10
What is the expntents of x5 - 3x4 plus x2 - 4 plus 5x4 plus 3x2 plus 2x plus 1?
x^5+2x^4+4x^2+2x-3
Find the sum 3x2 plus 2x plus 3 plus x2 plus x plus 1?
3x2 + 2x + 3 + x2 + x + 1 = 4x 2+ 3x + 4
What must be added to make x² - 2x plus 5 a perfect square?
negative four: x2 - 2x + 5 = x2 - 2x + 5 - 4 = x2 - 2x + 1 = (x - 1)2
Quotient and remainder of 3X4 plus 2X3 minus X2 minus x minus 6 divided by X2 plus 1?
(3x4 + 2x3 - x2 - x - 6)/(x2 + 1)= 3x2 + 2x - 4 + (-3x - 2)/(x2 + 1)= 3x2 + 2x - 4 - (3x + 2)/(x2 + 1)where the quotient is 3x2 + 2x - 4 and the remainder is -(3x + 2).
What are solutions for x2 plus 10x plus 1 equals -12 plus 2x?
x2+10x+1 = -12+2x x2+8x+13 = 0 The solution: x = -4 + the square root of 3 or x = -4 - the square root of 3
What is the solution to x2 plus 10x plus 1 equals -12 plus 2x?
x2+10x+1 = -12+2x x2+10x-2x+1+12 = 0 x2+8x+13 = 0 Solving by using the quadratic equation formula: x = - 4 - or + the square root of 3
How do you simplify 8z plus 5 - 2x -1?
By collecting like terms: 8z+4-2x
