3x2 + 2x + 3 + x2 + x + 1 = 4x 2+ 3x + 4
3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x + 2) - 4(x + 2) = (x + 2)(3x - 4).
The value of y in the equation -2x plus 4y -4, is 1 plus x/2.
It is written in descending order.
If the missing signs are all pluses, that's 4x2 + 3x + 3
(2x + 1) + (x*x - 2x + 1) = x^2 + 2x - 2x + 1 + 1 = x^2 + 2
if you rearrange it, it becomes 4y + 8 = 3x2 -2x +1 4y = 3x2 -2x -7 y= (3x2 -2x -7)/4 which is a parabola
If it is 3x2 + 4 = 2x + 4, then you can subtract 4 from both sides, and get 3x2 = 2x, and then x = 2/3
3x2 + 2x - 21 = (3x - 7) (x + 3)
2x+3x2 = x (2+3x)
If the original is 2x + 3x2 + 6 + 5x3, you should rearrange the terms in order of exponent:5x3 + 3x2 + 2x + 6
That depends on whether or not 2x is a plus or a minus
3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x + 2) - 4(x + 2) = (x + 2)(3x - 4).
if: f(x) = x3 - 4xe-2x Then: f'(x) = 3x2 - [ 4e-2x + 2(4x / -2x) ] = 3x2 - 4e-2x + 4
x^5+2x^4+4x^2+2x-3
2x2 + x2 = 3x2
3(x2 - 2x + 3)
Yes.