Q: How do you simplify an expression in the format of 4a2 plus 4ab - y2 plus b2?

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3a4 - 2a2 + 5a - 10 - 2a4 + 4a2 + 5a - 2 = a4 + 2a2 + 10a - 12 = a4 + (2a - 2)(a + 6)

No.

If a is an integer then 4 divides 4a2 so it cannot be a prime. If a = 0 then 4a2 = 0 and cannot be simplified further If a = 1 then 4a2 = 4 = 2*2 If a is an integer > 1, then 4a2 = 2*2*a*a If a is not an integer, then there are too many possible options for the answer.

4a2+ 25 does not factor over the real number field. In the complex numbers , it factors as (2a +5i)(2a - 5i). This is because i2 = -1, so 4a2 + 25 = 4a2 - (- 25) = 4a2 - 25(-1) = 4a2 - 25i2

4a2 - 20ab2 + 25b4 (2a - 5b2)(2a - 5b2) (2a - 5b2)2

That factors to 4(a - b)(a + 3b)

(x + 4)(4x - 1)

4a2 - 9a + 5 = 4a2 - 4a -5a + 5 = 4a(a - 1) - 5(a - 1) = (4a - 5)(a - 1)

(2a + c)(4a2 - 2ac + c2)

(2a + 1)(4a2 - 2a + 1)

Assuming multiplication, it's 4a2.

4a3 - 4a2 = 4a2*(a - 1)

4a2+4ab+b2 in2

√20a2b = √4a2 * √5b = 2a√5b the answer is 2a times radical 5b.

2A plus 3B times 2A - 3B = 4A2 - 9B2; this is an example of the general formula (a + b)(a - b) = a2 - b2.

4a2

It is 4a2.

(2a + 5)(2a - 5)

(2a + 1)(2a - 5)

2(2a2 - 31)

2a

12a4 + 16a64a4(3 + 4a2)=========

Assuming the missing signs are pluses, that factors to (4a + 3)(a + 3)

The LCM of 4a2b and 6a10b is 12a10b

(4a - 1)(a - 4)

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