4x2+20x+25 (2x+5)^2
362+60x+25 (6x+5)(6x+5)
(x-5i)(x+5i)
(6x + 5)(6x + 5) or (6x + 5)2
x2 + 25 doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: Zero plus or minus 5i times the square root of 1.x = 5ix = -5iwhere i is the square root of negative one.
4a^2 - 25 can be factored as (2a + 5)(2a - 5) using the difference of squares formula, where a is a variable.
x2 + 10y + 25 doesn't factor neatly. If that was x2 + 10x + 25, it would factor to (x + 5)(x + 5) or (X + 5)2
4n-20n+25
4x2+20x+25 (2x+5)^2
362+60x+25 (6x+5)(6x+5)
5(2r + 5)
4x+516x2 + 40x + 25= (4x + 5) (4x + 5)
(4x + 5)(4x + 5)
Factor the polynomial x2 - 10x + 25. Enter each factor as a polynomial in descending order.
(2x - 5)(2x - 5)
(x-5i)(x+5i)
(x - 4)(x - 25)