4a2 + 4ab - y2 + b2
You cannot simplify this expression because it does not contain like terms, but you can factor it such as:
4a2 + 4ab - y2 + b2
= (4a2 + 4ab + b2) - y2
= (2a + b)2 - y2
= [(2a + b) - y][(2a + b) + y]
Assuming multiplication, it's 4a2.
2A plus 3B times 2A - 3B = 4A2 - 9B2; this is an example of the general formula (a + b)(a - b) = a2 - b2.
You complete the squares. y = ax2 + bx + c = (ax2 + b/2a)2 + c - b2/(4a2)
One side of the square, RA, is 2a cm. So the area of the square is (2a)2 = 4a2 cm2
It is 4a2.
= 4a2 + 2ab 2b2
3a4 - 2a2 + 5a - 10 - 2a4 + 4a2 + 5a - 2 = a4 + 2a2 + 10a - 12 = a4 + (2a - 2)(a + 6)
If a is an integer then 4 divides 4a2 so it cannot be a prime. If a = 0 then 4a2 = 0 and cannot be simplified further If a = 1 then 4a2 = 4 = 2*2 If a is an integer > 1, then 4a2 = 2*2*a*a If a is not an integer, then there are too many possible options for the answer.
No.
4a2+ 25 does not factor over the real number field. In the complex numbers , it factors as (2a +5i)(2a - 5i). This is because i2 = -1, so 4a2 + 25 = 4a2 - (- 25) = 4a2 - 25(-1) = 4a2 - 25i2
4a2 - 20ab2 + 25b4 (2a - 5b2)(2a - 5b2) (2a - 5b2)2
That factors to 4(a - b)(a + 3b)
4a2
4a2 - 9a + 5 = 4a2 - 4a -5a + 5 = 4a(a - 1) - 5(a - 1) = (4a - 5)(a - 1)
Assuming multiplication, it's 4a2.
(2a + 1)(4a2 - 2a + 1)
(2a + c)(4a2 - 2ac + c2)