To solve the equation 2*pi*r^2 + 2*pi*r*h you use the quadratic formula. r= [ -piáh ±?(pi_áh_+2áAápi)]/ (2ápi). You then get r>0 --> r= [ -piáh +?(pi_áh_+2áAápi)]/ (2ápi) .
The total surface area of a cylinder can be found using the formulaA = 2(pi)r2 + 2(pi)rh or A = 2(pi)(r2 + rh)2 (pi x radius squared) = both ends of the cylinderpi x (2 radius) x height = area along the cylinder's side (circumference x height)
There are two ends, each of area {pi}r2 and the side which can be worked out by cutting the cylinder down (from end to end) and unrolling; one length is the cylinder height (h), the other is the circumference of the end (2{pi}r), giving 2{pi}rh. Area = 2x({pi}r2) + 2{pi}rh Area ~= 2x3.14x112 + 2x3.14x11x11 Area ~= 1520.5in2
The formula for surface area of a cylinder is: 2(pi)r2+2(pi)rh. r= radius h= height.
Total Surface Area = 2Ï€r2 + 2Ï€rh = 2Ï€r(r + h) = 2Ï€*2(2 + 8) = 40Ï€ cm2 = 125.664 cm2 approx.
The area of a cylinder = 2πr2 + 2πrh, where π is pi (3.14159...), r is the radius of the top and bottom, and h is the height. Click on the related link below for a tutorial on how to find the area of a cylinder.
The total surface area of a cylinder can be found using the formulaA = 2(pi)r2 + 2(pi)rh or A = 2(pi)(r2 + rh)2 (pi x radius squared) = both ends of the cylinderpi x (2 radius) x height = area along the cylinder's side (circumference x height)
It depends on the genotype of the Rh+ parent. If that person is heterozygous, then yes there is a 50% chance of an Rh- baby.Father's Group (negative)Mother's Group (positive heterozygous)Rh +Rh -Rh -Rh +, Rh -Rh -, Rh -Rh -Rh +, Rh -Rh - Rh -http://www.bloodbook.com/inherited.htmlIf the positive parent is homozygous, the baby will be positive:Father's Group (negative)Mother's Group (positive homozygous)Rh +Rh +Rh -Rh +, Rh -Rh +, Rh -Rh -Rh +, Rh -Rh + Rh -
Genotype determines the rh phenotype. The two alleles for rh factor are rh+ (rh positive) and rh- (rh negative). The rh+ allele is dominant.
There are two ends, each of area {pi}r2 and the side which can be worked out by cutting the cylinder down (from end to end) and unrolling; one length is the cylinder height (h), the other is the circumference of the end (2{pi}r), giving 2{pi}rh. Area = 2x({pi}r2) + 2{pi}rh Area ~= 2x3.14x112 + 2x3.14x11x11 Area ~= 1520.5in2
Father is Rh-Rh-Positive blood type has two options so mother could be Rh+Rh+ or Rh+Rh- and so :Rh-Rh- X Rh+Rh+all kids will be positivethe second option isRh-Rh- X Rh+Rh-50% of the kids will be negativethe other 50% will be positive.
there is no problem with that, your Rh+ comes from your mother :) ur father genotype is Rh-Rh- your mother should be Rh+Rh+ or Rh+Rh- so you took one Rh- from your father and one Rh+ from your mother the result will be Rh+Rh- and because the +ve propriety is more dominant your blood type will be +ve even if you have the mix of Rh+Rh-
There are two genes that controll the traits. Since Rh+ is a dominant character, it could be expresssed even in the hterzygous condition. But Rh- could be expressed in the homozygous recessive conditions also. The father is Rh+ that means he could be either Rh+Rh+ or he could be Rh+Rh- and the mother is Rh-Rh-. The father should be Rh+Rh- type. So the gametes formed are of type Rh+and Rh-. When the Rh- gamete of male combine with the of Rh- female gamete the offspring is Rh-, with genotype Rh-Rh-.
in science the positive blood type has two Geno-types :Rh+ Rh- or Rh+Rh+and the negative blood type has only one Geno-type :Rh- Rh-there are 3 possibilities :Rh + Rh- X Rh - Rh- 50% of kids will be Rh+ 50% will be Rh-Rh+ Rh+ X Rh - Rh- 100% of kids will be Rh+Rh+ Rh- x Rh+ Rh- either possibility exists in theory 25% could be Rh -
That is always possible if both the parents are heterozygous for Rh antigen gene. It means that both the parents. There are 2 different alleles for the Rh factor known as Rh+ and Rh-.Someone who is "Rh positive" or "Rh+" has at least one Rh+ allele, but could have two. Their genotype could be either Rh+/Rh+ or Rh+/Rh-. Someone who Rh- has a genotype of Rh-/Rh-. If their genotypes are Rh+/Rh-, then their is possibility of of Rh- also.Rh factorPossible genotypesRh+Rh+/Rh+Rh+/Rh-Rh-Rh-/Rh-Prof. A.L. Bhatiahttp://www.competition-india.blogspot.com/http://www.albhatia.inType O blood is also recessive to type A, so both parents could be heterozygous type A's. Their genotypes would have to be A/O.
The formula for surface area of a cylinder is: 2(pi)r2+2(pi)rh. r= radius h= height.
the geno type for O- is ( ii Rh-Rh- ) the geno type for B- is ( IBIB Rh-Rh- ) or ( IBi Rh-Rh-) they can have a child with O type if the genes was (ii Rh-Rh-) and (IBi Rh-Rh-) in a 50%. but they can't have an (O+) because both parents are Rh(negative).
Surface are of a cylinder: 2(pi)r2 + 2(pi)rh Volume of a cylinder: 2(pi)r2h [pi = 3.14159..., r = radius of the cylinder's cross section, h = height of the cylinder]