How do you solve (x 2)(x 1)(x-1)(x 7)?

Answer 1

x2 + 2x - 7 is a quadratic polynomial. Every polynomial defines a function called P. Any value of x for which P(x) = 0 is a root of the equation and a zero of the function.

x2 + 2x - 7 = 0 add 1 and 7 to both sides

x2 + 2x + 1 = 8

(x + 1)2 = 8 take the square root of both sides

x + 1 = ± √8 subtract 1 to both sides

x = -1 ± 2√2

Thus, the roots of the equation are -1 - 2√2 and -1 + 2√2.