x + 2x = 33 3x = 33 3x/3 = 33/3 x = 11
meant to be e^x = 2e^1-2x
x=5.54x+1= 2x+12-1 -14x=2x+11-2x -2x2x=11/2 /2x=5.5
2x - 4 = -10 2x = -10 +4 2x = -6 x = -3
2x + 7 = 1 Therefore, 2x = -6 x = -6/2 x = -3
-2x+13y=11 13y=2x+11 y=2x/13 + 11/13
2x+3 = -11 2x = -11-3 2x = -14 x = -7
2x - 5 = 11 2x = 11 + 5 2x = 16 2x /2 = 16 /2 x = 8
To solve this equation we have to isolate and solve for x. So: 2x-6= x+5 +6 +6 2x = x+11 -x -x x = 11 So x=11.
If 2x + 5 = 11, then 11 - 5 = 2x 6 = 2x 3 = x
2x - 13 x = 24 -11x = 24 -11x/-11 = 24/-11 x = -2 2/11
2x/3 = 8 + 4x2x = 24 + 12x-24 = 10x-2.4 = x
x + 2x = 33 3x = 33 3x/3 = 33/3 x = 11
2x+a=p 2x=p-a x=.5p-.5a
2x + 3y = 11Subract 2x from each side:3y = 11 - 2xDivide both sides by 3:y = 11/3 - (2/3)x
You can't solve a formula with no equals sign
It's called "elementary algebra".It looks like this:2x = 5Using the axiom "If equals are divided by equals, the quotients are equal.",divide each side of the equation by 2:x = 2.5